retrieve binary data back
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I have a binary data as
00 10 11 01 10 11 11 01
I need to replace this data as if
00 = 0
01 = 1
10 or 11 = *
if i get a new data as below
0 * * 1 * * * 1
can you suggest any way to get back the binary data
00 10 11 01 10 11 11 01
1 comentario
Respuesta aceptada
Más respuestas (2)
madhan ravi
el 18 de Mzo. de 2019
Editada: madhan ravi
el 18 de Mzo. de 2019
c=strjoin(regexp(c,'\d{2}+','match')); % for safety measure
% ^----- your original binary data
Actual_datas={'00','01','10|11',' '};
Replace_with={'0','1','*',''};
D=regexprep(c,Actual_datas,Replace_with)
Image Analyst
el 17 de Mzo. de 2019
Use strrep(). Try this:
str = '00 10 11 01 10 11 11 01'
% Make the length a multiple of three.
while rem(length(str), 3) ~= 0
str = [str, ' '];
end
% Make replacements
% 00 = 0
% 01 = 1
% 10 or 11 = *
str = strrep(str, '00 ', '0 ')
str = strrep(str, '01 ', '1 ')
str = strrep(str, '10 ', '* ')
str = strrep(str, '11 ', '* ')
% If desired, trim off any trailing or leading spaces.
str = strtrim(str)
4 comentarios
Rik
el 17 de Mzo. de 2019
For a bitstream it might be safer to use a cellfun call, instead of relying on spaces.
Image Analyst
el 17 de Mzo. de 2019
I'm not really 100% sure if there are actually spaces in it or if she just put them in to make it easier to visualize the pairs of digits. Maybe she'll say.
I find cellfun() is too cryptic for beginners, but if you have an example, please post it.
Judging by the track record of Elysi I wouldn't call them a beginner anymore, but just in case other/future readers need an example (which assumes the spaces are not in the actual data):
data='0010110110111101';
replace_with={'00','0';'01','1';'10','*';'11','*'};
key_list=replace_with(:,1);
val_list=replace_with(:,2);
%check for even numbers:
if rem(numel(data),2)~=0
error('bits are not paired')
end
%convert to 1 pair per cell
datacell=mat2cell(data,1,2*ones(numel(data)/2,1));
% %loop through the replacer elements
% for n=1:numel(key_list)
% datacell(ismember(datacell,key_list{n}))=val_list(n);
% end
inds=cellfun(@(x) find_indices(x,key_list),datacell);
L= inds~=0;
datacell(L)=val_list(inds(L));
%convert back to a char array
result=cell2mat(datacell);
clc,disp(result)
%local function:
function inds=find_indices(element,key_list)
[~,inds]=ismember(element,key_list);
end
Elysi Cochin
el 18 de Mzo. de 2019
Editada: Elysi Cochin
el 18 de Mzo. de 2019
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