Find distance between point (1,3,1) and plane 3(x-2)+2(y-1)-3(z-1)=0

can't seem to find the commands for this.

Answer 1

[Andrei Bobrov]

fp = @(x)(x(:).' - [2, 1, 1])*[3;2;-3]; % your plane
x0 = [1,3,1];                           % your point
d = fp(x0)/norm([3;2;-3]) ;             % your distance