how we can store value in array using loop?

user(1).will = 0.5;
user(1).rep = 1;
user(1).bid = [3,5,7];
user(1).inter_time=4;

user(2).will = 0.9;
user(2).rep = 0.6;
user(2).bid = [6,5,7];
user(2).inter_time=7;

% Structure of Array of user set

task(1).bud = 8;
task(1).qua = 1;

task(2).bud = 9;
task(2).qua = 2;

task(3).bud = 7;
task(3).qua = 1;

%a = zeros(1,3*2);
%b=zeros(1,3*2);
%c=zeros(1,3*2);


  for i=1:2
      for j=1:3
          %fprintf('i=%d j=%d\n',i,j);
          if(not (user(i).bid(j)<=task(j).bud))
              continue;
          end
          
          com_data_quality = (user(i).will*user(i).rep/user(i).bid(j)*user(i).inter_time);
          
          
          %a((i-1)*3+j)= com_data_quality;
          %b((i-1)*3+j)=i; 
          %c((i-1)*3+j)=j;
         
          
          %c = sort(s,'descend');
          
          
          
          
          fprintf('value is %f task is=%d user is=%d \n', com_data_quality,j,i);
      end 
  end
  

OUTPUT:

value is 0.666667 task is=1 user is=1

value is 0.400000 task is=2 user is=1

value is 0.285714 task is=3 user is=1

value is 0.630000 task is=1 user is=2

value is 0.756000 task is=2 user is=2

value is 0.540000 task is=3 user is=2

This is ouput of my code but i want store this value in 3*3 matrix in which first row store value second row store corresponding task number and 3rd row store user...how it's possible in matlab?HELP ME

Answer 1

[Matt J]

 Values=nan(3,3); %<---ADD

for i=1:2
      for j=1:3
        
          if(not (user(i).bid(j)<=task(j).bud))
              continue;
          end
          
          com_data_quality = (user(i).will*user(i).rep/user(i).bid(j)*user(i).inter_time);
          
          Values(i,j)=com_data_quality;  %<--ADD
          
          
          
          fprintf('value is %f task is=%d user is=%d \n', com_data_quality,j,i);
      end 
  end