Contourf: fill inside instead of outside
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Marco Sammito
el 7 de Abr. de 2019
Comentada: DGM
el 26 de Jul. de 2024
Hi, how can I fill the area within the circle? At the moment Matlab fills the area outside. I would like the outside to be white and the inside to be filled. Thanks.
relamdt=-4:0.1:4;
imlamdt=-4:0.1:4;
[x,y]=meshgrid(relamdt,imlamdt);
axis square;
lamdt=x+i*y;
sig = (1 + lamdt);
v = [1,1];
contourf(x,y,abs(sig),v)
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Walter Roberson
el 8 de Abr. de 2019
Editada: Walter Roberson
el 8 de Abr. de 2019
contourf(x, y, -abs(sig), -v)
Alternately, possibly
[~,h] = contourf(x, y, abs(sig), v);
drawnow(); %seems to be needed to get NodeChildren created
bg = h.NodeChildren(2).ColorData;
h.NodeChildren(2).ColorData = uint8([255; 255; 255; 255]);
ax = ancestor(h,'axes');
ax.Color = bg;
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Más respuestas (2)
David Wilson
el 8 de Abr. de 2019
A quick hack (following the essence of your code) is
cmap = colormap; cmap(end,:) = [1,1,1]; colormap(cmap);
contourf(x,y,abs(sig),[0,1]);
axis square
Roberto Tumolo
el 26 de Jul. de 2024
What if one wants to extract the values shown inside and outside (suppose you don't know them because they come from a contour?
1 comentario
DGM
el 26 de Jul. de 2024
The way the question is posed makes it unclear what information we might have. From a contour()/contourf() object, we can know a set of discrete z-values associated with the given level curves, but unless we have access to the original zdata, we don't know the actual values between the level curves. If we don't have access to the object itself (e.g. if all we have is a saved figure as a raster image (a screenshot)), then things get more restricted.
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