how does a diff operation works for relational and logical cases with arrays ?

i was trying to work with diff operator after trying out sum[1 2 4 6]

diff([14 5 6 14 32])

ans=

-9 1 8 18

above statement is understandable.

diff([14 5 6 14 32]==14)

ans=

-1 0 1 -1

this i can't understand !

how is this working???

Answer 1

[madhan ravi]

A = [14 5 6 14 32]==14 % Split it into two lines
diff(A)

Answer 2

[Star Strider]

The argument creates a logical array:

Lv = [14 5 6 14 32]==14
Lv =
  1×5 logical array
   1   0   0   1   0

and logical arrayss become numeric when you do calculations with them:

D = diff(Lv)
D =
    -1     0     1    -1

Similarly:

v = [14 5 6 14 32];
LogicalIndexing = v(Lv)
Multiplication = v .* Lv 

LogicalIndexing =
    14    14

Multiplication =
    14     0     0    14     0