How can I solve a nonlinear model using Newton Raphson ?

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Mallouli Marwa
Mallouli Marwa el 15 de Jul. de 2019
Comentada: Mallouli Marwa el 25 de En. de 2020
Hi
How can I solve this nonlinear model using Newton Raphson ?
x1 +x2^2 +cos (x3) = 2
x1 +sin (x2) + x3^3 = 1
x3 +x2^3+x3^3 = 4

Respuesta aceptada

Stephan
Stephan el 25 de En. de 2020
One way:
result = fsolve(@fun,[1 1 1])
function F = fun(x)
F(1) = x(1) + x(2).^2 + cos(x(3)) - 2;
F(2) = x(1) + sin(x(2)) + x(3).^3 - 1;
F(3) = x(3) +x(2).^3 + x(3).^3 - 4;
end
gives:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
result =
-0.5583 1.3732 0.8329
  2 comentarios
John D'Errico
John D'Errico el 25 de En. de 2020
The best way to solve it. Don't use Newton-Raphson at all. :)
Mallouli Marwa
Mallouli Marwa el 25 de En. de 2020
If I want to use Newton Raphson.
How can we change it ?

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