How to extract only numerical values from cell into new column array?
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For this data:
"chb12_06.edf"
"1665 seconds"
"1726 seconds"
"3415 seconds"
"3447 seconds"
"chb12_08.edf"
"1426 seconds"
"1439 seconds"
"1591 seconds"
"1614 seconds"
"1957 seconds"
"1977 seconds"
"2798 seconds"
"2824 seconds"
"chb12_09.edf"
"3082 seconds"
"3114 seconds"
"3503 seconds"
"3535 seconds"
"chb12_10.edf"
"593 seconds"
"625 seconds"
"811 seconds"
"856 seconds"
Whis is a column in a larger cell array. I want to extract just the seconds value after each edf file, and possibly put them in a new array or matrix, eg:
{"chb12_06.edf" "1665 seconds" "1726 seconds" "3415 seconds" "3447 seconds" ; "chb12_08.edf" "1426 seconds" "1439 seconds" "1591 seconds" "1614 seconds" "1957 seconds" "1977 seconds" "2798 seconds" "2824 seconds"...}
I hope this makes sense what I'm trying to achieve, if not please feel free to clarify, thanks!
Respuesta aceptada
Más respuestas (1)
Stephane Dauvillier
el 15 de Jul. de 2019
Try this:
in=["chb12_06.edf"
"1665 seconds"
"1726 seconds"
"3415 seconds"
"3447 seconds"
"chb12_08.edf"
"1426 seconds"
"1439 seconds"
"1591 seconds"
"1614 seconds"
"1957 seconds"
"1977 seconds"
"2798 seconds"
"2824 seconds"
"chb12_09.edf"
"3082 seconds"
"3114 seconds"
"3503 seconds"
"3535 seconds"
"chb12_10.edf"
"593 seconds"
"625 seconds"
"811 seconds"
"856 seconds"]
notQuiteThat = regexp(in,"(\d+) second","once","tokens") % extarct only digits befor second
notQuiteThat = [notQuiteThat{:}] % delete empty candidate
theSeconds = str2double(notQuiteThat) % transform it into actual double value
3 comentarios
madhan ravi
el 15 de Jul. de 2019
Editada: madhan ravi
el 15 de Jul. de 2019
+1, note the data is a cell array not string array.
notQuiteThat = regexp(string(in),"(\d+) second","once","tokens")
As an alternative:
v=string(V); % V - data
sscanf(char(v(contains(v,'seconds'))),'%d seconds')
Z Liang
el 15 de Jul. de 2019
Stephen23
el 15 de Jul. de 2019
"..what does the parenthesis do in this instance?"
Read about tokens in regular expressions:
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