Repeating array row n times with change of indexes
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Joanna Widzinska
el 12 de Sept. de 2019
Respondida: Joanna Widzinska
el 24 de Sept. de 2019
Hello everyone,
I have matrix of 1 minute data of the household load (5760x2, where 1st column reflects minutes and second the load). I need to transform data into seconds, where every row will be repeated 60 times with the change of indexes.
Ex.
1min x1 1 x1
2min x2 -----------------> 2 x1
... .....
5760min x5760 60 x1
61 x2
...
120 x2 etc.
I tried many different options and now I think it's involved in multiplying the matrices, but I can't solve this properly.
Can somebody help me? Thanks!
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Shubh Sahu
el 18 de Sept. de 2019
Hello Jonna,
Let us suppose, the household data is in ‘a’, to repeat the number of rows repelem function is used:
u(:,2) = repelem(a(:,2),[60]);
u(:,1)=1:(5760*60);
for more information regarding repelem refer the following link:
3 comentarios
Shubh Sahu
el 19 de Sept. de 2019
Have a look on this, may it explains
clc;
clear all;
close all;
a=[1,5;2,7;3,8];% take a 3*2 matrix
u(:,2) = repelem(a(:,2),[60]);
u(:,1)=1:(size(a,1)*60);
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