How to leave only the elements that appear once per page?

I have a 3D array. I need to remove any elements that are in the same place but on the next page, and only use the first occurrence at that position a. Eg. so if all pages were to multiply the result would be 0.

I can't assume this 3D array will be the same size in any dimension so I can't hard code solutions such as isMember. I also can't use the unique built-in function because I don't descriminate against all repeating elements but only elements which share a position on pages.

For example, input: A(:,:,1) = [ 1 0 1];

A(:,:,2) = [ 1 1 0];

A(:,:,2) = [ 0 1 1];

the desired output is: A(:,:,1) = [ 1 0 1];

A(:,:,2) = [ 0 1 0];

A(:,:,2) = [ 0 0 0];

Answer 1

[Bruno Luong]

If I understand you correctly

% Test data
A=rand(2,2,5)>0.7

B = logical(A.*cumprod(cat(3,ones(size(A(:,:,1))),1-A(:,:,1:end-1)),3))

[Sanzhar Shaimerden]

Thanks! Very smart and elegant.