Precise Matrix Power: A^k
6 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Eric Schöneberg
el 14 de Oct. de 2019
Comentada: Eric Schöneberg
el 15 de Oct. de 2019
Hello,
I am currently fighting with (more than) double-precision numerics, with which I am not familiar, so the answer probably lies within this topic. I would like to calculate
with and but obviously the precision of will be bad for big k. Is there a datatype of which I am not aware, or any other trick that will help me? Thanks in advance. :)
0 comentarios
Respuesta aceptada
Rik
el 14 de Oct. de 2019
It will probably be helpfull to use the Symbolic Math Toolbox, and use the tips explained here. For mod(a^b,k) there is a direct function, but for your use case there doesn't seem to exist one.
1 comentario
Más respuestas (0)
Ver también
Categorías
Más información sobre Number Theory en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!