Writting a loop for calculating difference from previous result of first calculation
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Shahab Khan
el 25 de Oct. de 2019
Comentada: Shahab Khan
el 28 de Oct. de 2019
I have 4 variables.
Initial_value = 50;
minimum_Value = 25;
difference_value = 5;
remaining_value = (Result)
I am trying to write a peice of code which can do following operation automatically:
step 1: Initial_value - difference_value = remaining_value
step 2: remaining_value - difference_value = new_remaining_value
step 3: new_remaining_value - difference_value = new_remaining_value_2
.
.
.
.
last step: loop stops when remaining value is equal to or less than minimum_value
To simplify I setup this example:
step 1: 50 - 5 = 45
step 2: 45 - 5 = 40
step 3: 40 - 5 = 35
step 4: 35 - 5 = 30
step 5: 30 - 5 = 25
End of loop as it reached to 25 (minimum value)
I tried writing this but it only calculates till 1 step.
for i = 100
if remaning_value(i) > minimum_value
a(i) = initial_value(i) - difference_value;
initial_value(i) = remaining_value(i);
end
end
Kindly suggest how shall i acheive this goal.
0 comentarios
Respuesta aceptada
Stephen23
el 25 de Oct. de 2019
Initial_value = 50;
minimum_value = 25;
difference_value = 5;
remaining_value = Initial_value;
while remaining_value(end)>minimum_value
remaining_value(end+1) = remaining_value(end)-difference_value;
end
Giving:
remaining_value =
50 45 40 35 30 25
3 comentarios
Stephen23
el 26 de Oct. de 2019
Editada: Stephen23
el 26 de Oct. de 2019
"It should stop at 12.58 but it did not."
Think about how while loops actually work: they continue as long as a condition is true and by the time that condition is false, the cause of it being false (e.g. some value being greater than 12.02) has already been calculated and added to your data.
One simple solution is to remove the last element:
while remaining_value(end) >= minimum_value % note: >=
remaining_value(end+1) = remaining_value(end)-difference_value;
end
remaining_value(end+1) = []; % remove last element
See also:
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!