how can i find the intersection point between the two curves and the minimum point to the other curve?
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mohamed asran
el 26 de Oct. de 2019
Respondida: mohamed asran
el 9 de Nov. de 2020
k1=10^-4;k2=2*10^5
k2 = 200000
d=0.08;
a=50*10^-6:1*10^-6:100*10^-6;
cr =k1./a;
cf =k2*d.*a;
ctot =cr+cf;
plot(a,cr,a,cf,a,ctot)
title('optimal')
xlabel('cross section area')
ylabel('costs')
legend('cr','ctot','cf')
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Image Analyst
el 26 de Oct. de 2019
Do you want the (harder) analytical answer (like from the formula) or the (easier) digital answer from the digitized vectors, like
distances = abs(cf-cr)
[minDistance, indexAtMin] = min(distances);
y1AtMin = cf(indexAtMin)
y2AtMin = cr(indexAtMin)
aAtMin = a(indexAtMin)
hold on;
line([aAtMin, aAtMin], ylim);
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Image Analyst
el 26 de Oct. de 2019
MATLAB is NOT needed for an analytical solution. Haven't you taken a calculus course yet?
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