X = [struct(jjj).name,' seed ', seedno]; disp(X) is not printing seedno

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seedno=data.seed
X = [struct(jjj).name,' seed ', seedno];
disp(X)
any idea why disp(x) is not showing the seedno?
the ouput of disp(x) is:
K_0.045 seed
but it should be:
K_0.045 seed 0
I did not use ; after seedno to print it and is prints correclty:
seedno =
0

Respuesta aceptada

Stephen23
Stephen23 el 26 de Oct. de 2019
Editada: Stephen23 el 26 de Oct. de 2019
X = [struct(jjj).name,' seed ',num2str(seedno)];
disp(X)
Or using low-level commands:
fprintf('%s seed %d\n',struct(jjj).name,seedno)

Más respuestas (1)

Image Analyst
Image Analyst el 26 de Oct. de 2019
Editada: Image Analyst el 26 de Oct. de 2019
Because it's a number not a string. Try
seedno = sprintf('%.2f', data.seed)
X = [struct(jjj).name,' seed ', seedno]
disp(X)
or
seedno = sprintf('%.2f', data.seed)
X = [struct(jjj).name,' seed ', seedno]
fprintf('X = %s\n', X);

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