How to compare the closest value in the matrix?

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rupak katwal
rupak katwal el 30 de Oct. de 2019
Respondida: Fabio Freschi el 31 de Oct. de 2019
I have the three vectors from the reference values of one vector, i have to choose the closet value among other two vector?
suppose
if R is the reference vector
unknownM =0.8105 1.1581 0.6295 0.9594 0.8447 0.7103 0.8429 0.5372 0.9882 0.8924
then from the other two vector
sudoM =0.7768 1.1883 0.8918 0.6824 1.1393 0.6507 1.3433 1.2419 0.7456 1.1048
grepM = 0.8034 0.7853 1.0771 0.6649 0.5639 0.8384 0.6207 0.6000 0.6896 0.8011
for the first value of unkownM it should select the value of grepM an continous.
  2 comentarios
darova
darova el 31 de Oct. de 2019
Can you show the result you expect to see?
Adam Danz
Adam Danz el 31 de Oct. de 2019
The question isn't clear. As darova suggestion, some input/output pairs might be helpful in addition to another explanation of the problem.

Iniciar sesión para comentar.

Respuestas (1)

Fabio Freschi
Fabio Freschi el 31 de Oct. de 2019
% your data
unknownM = [0.8105 1.1581 0.6295 0.9594 0.8447 0.7103 0.8429 0.5372 0.9882 0.8924];
sudoM = [0.7768 1.1883 0.8918 0.6824 1.1393 0.6507 1.3433 1.2419 0.7456 1.1048];
grepM = [0.8034 0.7853 1.0771 0.6649 0.5639 0.8384 0.6207 0.6000 0.6896 0.8011];
% preallocation
closest = zeros(size(unknownM));
% errors
errSudoM = abs(sudoM-unknownM);
errGrepM = abs(grepM-unknownM);
% sudoM is closer
idx1 = errSudoM < errGrepM;
closest(idx1) = sudoM(idx1);
% grepM is closer
closest(~idx1) = grepM(~idx1);

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