How to convert a string of characters to numbers?

I have the following string obtained from a text file (the text file has a lot of info so I had to go and look for certain lines):
0 0 0 0 0.1 0 0 0 BlaBla
Another line might look like this
1 0.013 0.0156 -0.104 0.0376 0.0624 0.132 0.132 BlaBlaBla
By the way I'm reading the file everything is now a string of characters.
How can I convert that to a vector? Notice that the last column is a string of characters. The white spaces on the first line is different than on the second one too.
Any help is appreciated thanks.

 Respuesta aceptada

Matt Fig
Matt Fig el 28 de Sept. de 2012
Editada: Matt Fig el 28 de Sept. de 2012
str = '1 0.013 0.0156 -0.104 0.0376 0.0624 0.132 0.132 Bla';
T = regexp(str,'-*\d*\.*\d*','match');
V = cellfun(@str2double,T)

7 comentarios

Matt Fig
Matt Fig el 28 de Sept. de 2012
Editada: Matt Fig el 28 de Sept. de 2012
carlos Uribe comments:
"Thanks Matt that works when I have just one string...
Now my problem is that I have a cell of those strings (cell).
T = regexp(cell,'-*\d*\.*\d*','match');
works fine and gives me a cell T with many cells
V = cellfun(@str2double,T)
gives me a problem because I cannot input a cell there...
Any workarounds for this?"
Yes, just do the same for each element of T.
str = {'1 0.013 0.0156 -0.104 0.0376 0.0624 0.132 0.132 Bla'};
str(2) = {'22 0 3 0 0.1 0 0 0 BlaBla'};
T = regexp(str,'-*\d*\.*\d*','match');
V = cellfun(@str2double,T,'Un',0);
V{1}
V{2}
carlos Uribe
carlos Uribe el 28 de Sept. de 2012
I was just trying to figure out if there was kind of a "vectorized" way of doing it...given that right now I have 10^8 of those strings.
Matt Fig
Matt Fig el 28 de Sept. de 2012
You mean more vectorized than I showed above? How could it be more vectorized than what I showed above, since there are no MATLAB loops?
Jan
Jan el 28 de Sept. de 2012
V = str2double(T); % Without CELLFUN
carlos Uribe
carlos Uribe el 28 de Sept. de 2012
My bad..didn't see that you added two new values to cellfun...thanks for your help
Matt Fig
Matt Fig el 28 de Sept. de 2012
Jan, that returns nans here...

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Más respuestas (1)

Jan
Jan el 28 de Sept. de 2012
str = '1 0.013 0.0156 -0.104 0.0376 0.0624 0.132 0.132 Bla';
V = sscanf(str, '%g', 6);

1 comentario

Or for cell str:
V = cellfun(@(x) sscanf(x, '%g'),str,'Un',0);
Very nice... no call to REGEXP.

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