I don't know why the answer to this question was deleted, but I hope someone else checks this question
How can I make the cycle range symmetric around zero in rainflow ?
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farzad
el 24 de Dic. de 2019
Comentada: Star Strider
el 25 de Dic. de 2019
Hi All
I am using
rainflow( x, 'ext')
but the cycle ranges are not symmetric around zero. How can I make matlab do that ?
This is what I get from RainFlow command :
![Histogram-X.png](https://www.mathworks.com/matlabcentral/answers/uploaded_files/257170/Histogram-X.png)
As you see it seems like you are watching the graph from behind
instead , normally this is what I see as a histogram on internet you can see how the Cycle mean and Cycle average are swapped
![hh.jpg](https://www.mathworks.com/matlabcentral/answers/uploaded_files/257171/hh.jpeg)
Respuesta aceptada
Star Strider
el 25 de Dic. de 2019
After all that (and deleting my first Answer because it was not solving the problem), the solution appears to have turned out to be relatively simple.
This uses an example from the rainflow documentation (specifically, Cycle Counts of Timetable). Try it with your own data:
fs = 100;
t = seconds(0:1/fs:100-1/fs)';
x = randn(size(t));
TT = timetable(t,x);
figure
rainflow(TT) % Original
figure
rainflow(TT)
set(gca, 'View',[60 30]) % Rotated Using A Simple View Call To The Last Plotted Axes
producing this originally:
![1How can I make the cycle range symmetric around zero in rainflow (1) - 2019 12 25.png](https://www.mathworks.com/matlabcentral/answers/uploaded_files/257184/1How%20can%20I%20make%20the%20cycle%20range%20symmetric%20around%20zero%20in%20rainflow%20(1)%20-%202019%2012%2025.png)
and after the rotation:
![1How can I make the cycle range symmetric around zero in rainflow (2) - 2019 12 25.png](https://www.mathworks.com/matlabcentral/answers/uploaded_files/257185/1How%20can%20I%20make%20the%20cycle%20range%20symmetric%20around%20zero%20in%20rainflow%20(2)%20-%202019%2012%2025.png)
2 comentarios
Star Strider
el 25 de Dic. de 2019
As always, my pleasure!
I deleted my Answer so someone else could contribute, since my previous attempts were not successful. It turned out that I was just over-thinking this problem.
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