"Index exceeds the number of array elements"

Hello,
I am recieving this error:
Index exceeds the number of array elements (1).
Error in sym/subsref (line 890)
R_tilde = builtin('subsref',L_tilde,Idx);
Error in E_field (line 7)
Ey = matlabFunction(E(2));
Here is the function file the error is referencing:
function [Ex, Ey, Ez] = E_field()
syms x y z
R_s = 0.02;
V = 0;
epnaut = 8.854187E-12;
k = 1/(4*pi*epnaut);
Q = (V*R_s)/k;
r = [x, y, z];
E = (k*Q/norm(r)^3)*r;
Ex = matlabFunction(E(1));
Ey = matlabFunction(E(2));
Ez = matlabFunction(E(3));
end

1 comentario

Walter Roberson
Walter Roberson el 29 de En. de 2020
The posted code works for me. However you should using the 'vars' option of matlabFunction or else your function handle is not going to accept any arguments because your R values are all constants.

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 Respuesta aceptada

Matt J
Matt J el 29 de En. de 2020
Editada: Matt J el 29 de En. de 2020
Perhaps this is what you are looking for,
function [Ex, Ey, Ez] = E_field(x,y,z)
R_s = 0.02;
V = 0;
epnaut = 8.854187E-12;
k = 1/(4*pi*epnaut);
Q = (V*R_s)/k;
r = [x, y, z];
E = (k*Q/norm(r)^3)*r;
Ex = E(1);
Ey = E(2);
Ez = E(3);
end

9 comentarios

Matt J
Matt J el 29 de En. de 2020
Editada: Matt J el 29 de En. de 2020
Or perhaps this,
function [Ex, Ey, Ez] = E_field()
R_s = 0.02;
V = 0;
epnaut = 8.854187E-12;
k = 1/(4*pi*epnaut);
Q = (V*R_s)/k;
Ex = @(x,y,z) x*(k*Q/norm([x,y,z])^3) ;
Ey = @(x,y,z) y*(k*Q/norm([x,y,z])^3) ;
Ez = @(x,y,z) z*(k*Q/norm([x,y,z])^3) ;
end
Tom Keaton
Tom Keaton el 29 de En. de 2020
Why would using matlabFunction() not work here?
Also I am currently referencing this in another function as such. If I used this syntax, how would that change in the reference?
function bdip = bdipuniodefun(t,s)
%Using SI units
q = -1.60217662E-19;
m_e = 9.11E-31;
global Bx By Bz Ex Ey Ez
if isempty(Bx)
[Bx, By, Bz] = B_test();
end
if isempty(Ex)
[Ex, Ey, Ez] = E_test();
end
bdip = [s(4); s(5); s(6); (q/m_e)*(Ex(s(1),s(2),s(3)) + s(5)*Bz(s(1),s(2),s(3)) - s(6)*By(s(1),s(2),s(3))); (q/m_e)*(Ey(s(1),s(2),s(3)) + s(6)*Bx(s(1),s(2),s(3)) - s(4)*Bz(s(1),s(2),s(3))); (q/m_e)*(Ez(s(1),s(2),s(3)) + s(4)*By(s(1),s(2),s(3)) - s(5)*Bx(s(1),s(2),s(3)))];
end
Walter Roberson
Walter Roberson el 29 de En. de 2020
Your norm is 0. Multiply by x y z and you get 0 0 0. When you matlabFunction that without a vars option then matlab sees that the symvar([0 0 0]) is empty and decides that what is wanted is a function handle that takes no parameters and returns a 0 of constant size. If you provided a vars option you at least would get back a function handle that permitted parameters when it returned the scalar 0.0
@Matt J I get a new but the same error when I try using either of your recommendations:
Index exceeds the number of array elements (1).
Error in sym/subsref (line 890)
R_tilde = builtin('subsref',L_tilde,Idx);
Error in E_field (line 7)
Ey = matlabFunction(E(2));
Error in bdipuniodefun
Error in odearguments (line 90)
f0 = feval(ode,t0,y0,args{:}); % ODE15I sets args{1} to yp0.
Error in ode15s (line 150)
odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options, varargin);
Error in collisions7 (line 216)
[T,S] = ode15s(@bdipuniodefun, tspan, icv); %Matlab's ODE solver
Walter Roberson
Walter Roberson el 1 de Feb. de 2020
Could you remind us which MATLAB version are you using?
MATLAB Version: 9.6.0.1099231 (R2019a) Update 1
Operating System: Microsoft Windows 10 Pro Version 10.0 (Build 18363)
Java Version: Java 1.8.0_181-b13 with Oracle Corporation Java HotSpot(TM) 64-Bit Server VM mixed mode
Walter Roberson
Walter Roberson el 1 de Feb. de 2020
Is there a reason you are using global instead of persistent ? Is there some other function that will use the created Bx By Bz Ex Ey Ez ?
Tom Keaton
Tom Keaton el 4 de Feb. de 2020
Sorry I missed this question. The answer is yes which is why I am using it. I will show the code that causes this issue in another post.

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Más respuestas (1)

Walter Roberson
Walter Roberson el 1 de Feb. de 2020
V = 0;
V is 0.
Q = (V*R_s)/k;
V is 0, so Q will be 0.
E = (k*Q/norm(r)^3)*r;
Provided that norm(r ) is not 0 and k is not infinity, then because Q is 0, E is going to be
zeros(size(r))
symvar() of a vector of 0 is empty. matlabFunction() of a constant, when you do not use any 'vars' option, is a function handle that accepts no inputs and returns a scalar copy of the constant.
The original code that was posted does not give me an index exceeded matrix dimension when I test it in R2019a.

1 comentario

Tom Keaton
Tom Keaton el 4 de Feb. de 2020
Under this specific circumstance this does work for me now.

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