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Image Analyst
Image Analyst el 11 de Oct. de 2012

0 votos

Wouldn't it just go like this
difference = single(image1) - single(image2);
squaredError = difference .^ 2;
meanSquaredError = sum(squaredError(:)) / numel(image1);
rmsError = sqrt(meanSquaredError);
Of course you could compact that all into one line if you want.

5 comentarios

Mahua Nandy(Pal)
Mahua Nandy(Pal) el 14 de Oct. de 2012
Thanks a lot. Please let me know why single() has to be used?
Image Analyst
Image Analyst el 14 de Oct. de 2012
you need to use single so that you can have negative numbers. If your image is uint8 (0-255 gray levels like most images), then it is UNSIGNED, which means anything that should be negative will be clipped at zero:
smallNumber = uint8(5);
bigNumber = uint8(200);
u8 = smallNumber - bigNumber
s8 = single(smallNumber) - single(bigNumber)
In the command window:
u8 =
0
s8 =
-195
Mahua Nandy(Pal)
Mahua Nandy(Pal) el 16 de Oct. de 2012
Thank you for your lucid clarification.
MAT-Magic
MAT-Magic el 18 de En. de 2020
Editada: Image Analyst el 18 de En. de 2020
@Image Analyst, can I use this formula for two vectors having same length?
difference = single(image1) - single(image2);
squaredError = difference .^ 2;
meanSquaredError = sum(squaredError(:)) / numel(image1);
rmsError = sqrt(meanSquaredError);
?
Image Analyst
Image Analyst el 18 de En. de 2020
Yes, you can, but I'd use mean() instead of sum to simplify it:
differenceImage = single(image1) - single(image2);
squaredErrorImage = differenceImage .^ 2;
meanSquaredError = mean(squaredErrorImage(:)) % A scalar
rmsError = sqrt(meanSquaredError)
And if they're vectors of the same shape (row or column) then you don't even need the (:).

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Daniel Shub
Daniel Shub el 11 de Oct. de 2012
Editada: Daniel Shub el 11 de Oct. de 2012

0 votos

Just to be a little bit difference. If you have the DSP system toolbox you can do
step(dsp.RMS('Dimension', 'all'), x)
where x is your error signal. So in the case of two imagines (image1 and image2)
image1 = randn(128);
image2 = randn(128);
x = image1-image2;

6 comentarios

Image Analyst
Image Analyst el 11 de Oct. de 2012
Would x = cat(3, image1, image2)?
Daniel Shub
Daniel Shub el 11 de Oct. de 2012
IA what?
Image Analyst
Image Analyst el 11 de Oct. de 2012
He has two images, say image1 and image2 where image1 is the reference image and another image that is the misaligned one. He has attempted to "fix" (register) by aligning it with image1 and that "registered" image is image2. Where would those two images go into your formula?
Daniel Shub
Daniel Shub el 11 de Oct. de 2012
I got it, dsp.RMS calculates the RMS of an n-d signal. So to get the RMS error, x needs to be the error signal. In the case of two images x is the difference between the images.
Ishara Nipuni
Ishara Nipuni el 25 de En. de 2019
I calculated the RMS value of my image registration algorithm by using your code. But I can't understand how to do a validation for my registration algorithm with th RMS value. Can you tell me please how can I com to conclusions about the accuracy of my registration algorithm with the use of RMS values?
Ishara Nipuni
Ishara Nipuni el 25 de En. de 2019
I calculated the RMS value with getting the same image as image1 and image2. But the value was not zero. But I think that it should be zero. Can you please explain me about it?

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