How to find the element of a number if that number were to be placed in an ordered list?

For example:

list = (0:10)

number= 2.5

the element it is in-between is 3 and 4

What is the most efficient way of finding where 2.5 would lie in that list and which elements it would be in-between?

Is there a better way than doing a for loop?

for i = 1:length(list)
    if number > list(length(list))
       fprintf('it is greater than any the numbers')
    end
    if number == list(i)
       fprintf('it is element %d',i)
    end
    if number < list(length(list))
        if number > list(i)
            if number < list(i+1)
                fprintf('it is between element %d and %d ',i,i+1 )
            end
        end
    end
end

Answer 1

[Stephen23]

The robust solution:

>> ida = find(list<number,1,'last')
ida =  3
>> idb = find(list>number,1,'first')
idb =  4

Answer 2

[madhan ravi]

Between = [find(ismember(list1,fix(2.5))), find(ismember(list1,ceil(2.5)))]

[arthurk]

What about the case if its greater or smaller than any values in list?

[madhan ravi]

Looks like homework questions , google logical operators MATLAB.

[Stephen23]

Note that this will not work if the list does not contain the rounded number, e.g.:

>> list = 0:2:10
list =
    0    2    4    6    8   10
>> number = 2.5;
>> find(ismember(list,fix(2.5))) 
ans =  2
>> find(ismember(list,ceil(2.5))) % !!!!
ans = []

[madhan ravi]

Oops thank you for indicating Stephen.

[arthurk]

I'm trying to find the most efficient way. As you can see from my code I do have knowledge of using operators, however I'm trying to make it efficiently as possible without expending many lines of code.