Access the data from a Struct

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Susan
Susan el 30 de Mzo. de 2020
Comentada: Susan el 31 de Mzo. de 2020
I have a struct with fields
val = struct with fields:
abstract: [1×1 struct]
body_text: [72×1 struct]
when I extract the text data in body_text using "val.body_text.text" I got 72*1 struct. But when I try "A = val.abstract.text", I got only the first struct of the 72 structs. How can I put all these [72×1 struct] into A?
Thanks!
  3 comentarios
Ameer Hamza
Ameer Hamza el 30 de Mzo. de 2020
''so val.abstract.text is either invalid reference or is the name of the 1x1 struct under val.abstract'''
Not necessarily. For example
>> s.text = '123';
s.xyz = 2;
val.abstract = s;
val.body_text = repmat(s, 1, 72);
>> val
val =
struct with fields:
abstract: [1×1 struct]
body_text: [1×72 struct]
>> val.abstract.text
ans =
'123'
Susan
Susan el 30 de Mzo. de 2020
Sorry for the confusion! What I meant was "But when I try "A = val.body_text.text", I got only the first struct of the 72 structs"

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Ameer Hamza
Ameer Hamza el 30 de Mzo. de 2020
Editada: Ameer Hamza el 30 de Mzo. de 2020
Try this, if the data in the field 'text' is scalar
A = [val.abstract.text];
If it is vector than try
A = {val.abstract.text};
  5 comentarios
Ameer Hamza
Ameer Hamza el 31 de Mzo. de 2020
Try the following code. Place it one directly above the JSON files, or you can modify the first line according to the path of your JSON files. It will read all files, and gather their abstract.text and body_text.text fields into one struct. It then writes the final struct as a JSON file.
files = dir('JSON files/*.json');
s = struct('abstract', [], 'body_text', []);
for i=1:numel(files)
filename = fullfile(files(i).folder, files(i).name);
data = jsondecode(fileread(filename));
if ~isempty(data.abstract)
s.abstract = [s.abstract; cell2struct({data.abstract.text}, 'text', 1)];
end
if ~isempty(data.body_text)
s.body_text = [s.body_text; cell2struct({data.body_text.text}, 'text', 1)];
end
end
str = jsonencode(s);
f = fopen('filename.json', 'w');
fprintf(f, '%s', str);
fclose(f);
Susan
Susan el 31 de Mzo. de 2020
Thank you so much! I really appreciate your help.

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