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issue in converting matrix to rgb image

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PRACHI Sood
PRACHI Sood el 3 de Abr. de 2020
Comentada: PRACHI Sood el 12 de Mayo de 2020
I was trying to replace pixel values by their corresponding 3x3 non overlapping block. since the output matrix was of type double I converted it to uint8 type.
But when I displayed the image in the figure window it was gray instead of coloured image . I tried cat(3, gray, gray, gray) but image is still colourless.
What did I do wrong?
img= imread('C:\Users\prach\MATLAB programs\Lenna_(test_image).png');
new = blockproc(img, [10 10], fun);
new1= uint8(new);
imshow(new1)
rgbnew= cat(3, new1, new1, new1);
imshow(rgbnew)
  7 comentarios
Walter Roberson
Walter Roberson el 11 de Mayo de 2020
sounds like you are using a slightly older version of MATLAB that does not permit multiple dimensions. In that case as long as the image grayscale, median(block_struct.data(:))
But if you are dealing with rgb then it gets a bit messier,
median(reshape(block_struct.data,[],1,3),1)
PRACHI Sood
PRACHI Sood el 12 de Mayo de 2020
@Walter Roberson
The median(block_struct.data(:)) worked perfectly. Thankyou very much.

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Respuestas (1)

Image Analyst
Image Analyst el 10 de Mayo de 2020
You need to use imsplit() to get the individual color channels, and then process them and combine them with cat(3).
  4 comentarios
Image Analyst
Image Analyst el 11 de Mayo de 2020
The blockproc_color_means.m demo gives this image. Is it like you want?
PRACHI Sood
PRACHI Sood el 12 de Mayo de 2020
Apologies for the incomplete information. Attaching the .m file and the image.
Yes, the output images shown in your last comment as output of blockproc_color_means.m is my desired output. I will go through the list of demos you have provided. Thankyou very much.

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