how to solve an equation where the unknown is an integration boundry for a numerical integration?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
David Welling
el 19 de Abr. de 2020
Respondida: David Welling
el 19 de Abr. de 2020
I need to solve this equation in the form
for x where A is a constant and f a known function, which has to be integrated numerically.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/285826/image.png)
However, when i define this function and try to solve, i get the error
"Error using integral (line 85)
A and B must be floating-point scalars."
Apparently I cannot put the variable I need to solve for in the boundry of the integral.
How can this be done?
Below is the code. I know, it is a lot of constants.
P_ep = @(z) P_c.*(((exp(-(1/4).*(z./omega_c).^(5/12))).*((z./omega_c).^(3./2)))+(((4./C).*(2.84-0.92.*(1-cos(pi.*((sqrt(R.*z.*(z./(1.9.*omega_c)).^(0.14.*exp(23.*(S_y./E)))))./R))))).*(1-exp(-(1./25)*(z./omega_c).^(5./9))).*(z./omega_c)));
syms omega_m_ep
omega_m = solve(integral(P_ep,omega_c,omega_m_ep) == (0.5 * m * V_1 ^2)- ((8/15)*E*sqrt(R)*omega_c^(5/2)),omega_m_ep);
7 comentarios
James Tursa
el 19 de Abr. de 2020
You need to pass fslove a function handle, and that function handle then needs to call integral.
Respuesta aceptada
Más respuestas (0)
Ver también
Categorías
Más información sobre Calculus en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!