store variables in a for loop

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Davide Cerra
Davide Cerra el 21 de Abr. de 2020
Comentada: Sriram Tadavarty el 21 de Abr. de 2020
Hello,
i m trying to obtain a set of coordinates for this:
function [x, y] = gencircle(xo,yo,r,N)
x=(xo+r*cos(theta))';
y=(yo+r*sin(theta))';
clear all
xo=[1 2 3 4 5 6 7 8];
yo=[-1 -0.5];
r=0.01;
N=10;
theta=2*pi/N*(1:N+1);
th=0.00235;
for j=1:length(yo)
for i=1:length(xo)
[xout(:,i), yout(:,j)]=gencircle(xo(i),yo(j),r,N)
[xin(:,i), yin(:,j)]=gencircle(xo(i),yo(j),r-th,N)
end
end
for j=1:length(yo)
for i=1:length(xo)
aa=[xout(:,i),yout(:,j)]
end
end
how can i store the vector aa for each loop?
Thanks

Respuesta aceptada

Sriram Tadavarty
Sriram Tadavarty el 21 de Abr. de 2020
Editada: Sriram Tadavarty el 21 de Abr. de 2020
Hi Davide,
You can make the following modification to the code as shown below, which stores all the loop iteration values in the variable aa:
clear all
xo=[1 2 3 4 5 6 7 8];
yo=[-1 -0.5];
r=0.01;
N=10;
theta=2*pi/N*(1:N+1);
th=0.00235;
for j=1:length(yo)
for i=1:length(xo)
[xout(:,i), yout(:,j)]=gencircle(xo(i),yo(j),r,theta);
[xin(:,i), yin(:,j)]=gencircle(xo(i),yo(j),r-th,theta);
end
end
aa = zeros(size(xout,1),2,length(yo)*length(xo)); % Initialize the variable
tmp = 1;
for j=1:length(yo)
for i=1:length(xo)
aa(:,:,tmp)=[xout(:,i),yout(:,j)];
tmp = tmp+1;
end
end
% aa will be a variable of size length(xout) x 2 x (loop iterations)
% loop iterations here is equal to the product of length(yo) and length(xo) (implies 16)
% Each iteration value can be accessed by indexing from 3rd dimension,
% implies for example fifth iteration can be accessed with aa(:,:,5)
function [x, y] = gencircle(xo,yo,r,theta)
x=(xo+r*cos(theta))';
y=(yo+r*sin(theta))';
end
Hope this helps.
Regards,
Sriram
  4 comentarios
Davide Cerra
Davide Cerra el 21 de Abr. de 2020
incredibly useful, thanks!
Sriram Tadavarty
Sriram Tadavarty el 21 de Abr. de 2020
Please do accept the answer, if helped

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