I need to speed up this code, T is a table with 5 columns and approximately 1 million rows. The code is doing what I need but it is pretty slow, it takes 1 hour to do the calculation. Someone can help?
Thanks in advance
rmsA = zeros(height(T),1);
for i=1:height(T)
tf = isbetween(T.VarName1,T.VarName(i)-minutes(2),T.VarName(i)+minutes(2));
xA = T.VarName2(tf);
rmsA(i) = rms((xA-993)/102.04);
end

2 comentarios

BALAJI KARTHEEK
BALAJI KARTHEEK el 23 de Abr. de 2020
Use parallel computing and parfor loops are available in matlab exactly to solve these type of problems
darova
darova el 23 de Abr. de 2020
Can you attach sample data for experiments?

Iniciar sesión para comentar.

Respuestas (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 23 de Abr. de 2020

1 voto

To process date data format is slow. Thus, you can convert all into a serial date number using datenum() that shall speed up the simulation process.
good luck

2 comentarios

Emiliano Ascenzi
Emiliano Ascenzi el 24 de Abr. de 2020
How can I apply isbetween to datenum output? I don't know how much 2 minutes are worth in that form
Med Aymane Ahajjam
Med Aymane Ahajjam el 28 de Jul. de 2021
treat them like you would with normal numbers : .. < .. < ..

Iniciar sesión para comentar.

Categorías

Productos

Versión

R2019b

Preguntada:

el 23 de Abr. de 2020

Comentada:

el 28 de Jul. de 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by