Speed up for loop

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Emiliano Ascenzi
Emiliano Ascenzi el 23 de Abr. de 2020
Comentada: Med Aymane Ahajjam el 28 de Jul. de 2021
I need to speed up this code, T is a table with 5 columns and approximately 1 million rows. The code is doing what I need but it is pretty slow, it takes 1 hour to do the calculation. Someone can help?
Thanks in advance
rmsA = zeros(height(T),1);
for i=1:height(T)
tf = isbetween(T.VarName1,T.VarName(i)-minutes(2),T.VarName(i)+minutes(2));
xA = T.VarName2(tf);
rmsA(i) = rms((xA-993)/102.04);
end
  2 comentarios
BALAJI KARTHEEK
BALAJI KARTHEEK el 23 de Abr. de 2020
Use parallel computing and parfor loops are available in matlab exactly to solve these type of problems
darova
darova el 23 de Abr. de 2020
Can you attach sample data for experiments?

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Respuestas (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov el 23 de Abr. de 2020
To process date data format is slow. Thus, you can convert all into a serial date number using datenum() that shall speed up the simulation process.
good luck
  2 comentarios
Emiliano Ascenzi
Emiliano Ascenzi el 24 de Abr. de 2020
How can I apply isbetween to datenum output? I don't know how much 2 minutes are worth in that form
Med Aymane Ahajjam
Med Aymane Ahajjam el 28 de Jul. de 2021
treat them like you would with normal numbers : .. < .. < ..

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