Modify matrix for partial plot
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
jojo
el 9 de Mayo de 2020
Comentada: Walter Roberson
el 9 de Mayo de 2020
How can I modify the for loops to create a bracket-shaped domain? In otherwords, I would like to plot everything and omit the first quadrant. Thank you!
clear; close all; clc
n = 40;
x = linspace(0,8,n); dx = x(2)-x(1); y = x; dy = dx;
U = zeros(n);
U(n,1:n/2) =10;
U(n/2,n/2:n-1) =0;
U(1,1:n-1) = 10;
U(2:n,n/2) = 0;
U(1:n/2,n) = 7;
U(n/2:n,n/2) = 0;
alpha=1;
ddt = 1/(4*(1/dx^2+1/dy^2));
for w=1:1000
V = U;
for i = 2:n/2-1
for j = 2:n-1
U(i,j) =ddt*((V(i+1,j)-2*V(i,j)+V(i-1,j))/dx^2+ (V(i,j+1)-V(i,j)+V(i,j-1))/dy^2)+ V(i,j);
end
end
end
figure(1)
contour(y,x,U)
figure(2)
surf(y,x,U)
5 comentarios
Walter Roberson
el 9 de Mayo de 2020
surf(y, x, Uc)
The 'edgecolor', 'none' just controls drawing the edges of each face. When you have many faces, the edges start to take over the visual impression, because the edges are constant width even when the faces get small.
Walter Roberson
el 9 de Mayo de 2020
x and y are both increasing, and you are using x for rows and y for columns. Which is the "first quadrant" ?
(x=0,y=0) (x=0,y=4) (x=0,y=8)
A B
(x=4,y=0) (x=4,y=4) (x=4,y=8)
C D
(x=8,y=0) (x=8,y=4) (x=8,y=8)
Respuesta aceptada
darova
el 9 de Mayo de 2020
Editada: darova
el 9 de Mayo de 2020
Here are your bourndary conditions
n = 40;
x = linspace(0,8,n); dx = x(2)-x(1); y = x; dy = dx;
U = zeros(n);
U(n,1:n/2) =10;
U(n/2,n/2:n-1) =0+10;
U(1,1:n-1) = 10;
U(2:n,n/2) = 0+10;
U(1:n/2,n) = 7+3;
U(n/2:n,n/2) = 0+10;
alpha=1;
ddt = 1/(4*(1/dx^2+1/dy^2));
h = imagesc(U);
view(2)
Something is missing
I made some changes to your script. It still doesn't work
2 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Surface and Mesh Plots en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!