How to reverse a number

Hi, I want to reverse a number, not a vector, like 8549 to 9458. I used fliplr , or flipud, or y = x(end:-1:1), They just work for row vector. Please, help. Thank you

Answer 1

[Azzi Abdelmalek]

a=8549
out=str2num(fliplr(num2str(a)))

[Aritra Chatterjee]

Great!!! Great!!!!

[János Stenszky]

Thanks!

[Uchechukwu Obimma]

Thanks

Answer 2

[Roger Stafford]

@Jessica: Let x be a non-negative integer. Then y will have the decimal digits of x in reversed order.

   y = 0;
   while x > 0
     t = mod(x,10);
     y = 10*y+t;
     x = (x-t)/10;
   end

[Kunal Kabi]

Thank you sir because of you i got the idea @RogerStafford.

[ABHAS BHATIA]

Thanks for the solution @Jessica

Answer 3

[Kunal Kabi]

If you want to find palindrome numbers between two range here is the answer

clc;
clear all;
close all;
num=input('Enter first range:');
num1=input('Enter second range:');
for i=num:num1
temp=i;
reverse=0;
   while temp > 0
     t = mod(temp,10);
     reverse = 10*reverse+t;
     temp = (temp-t)/10;
   end
 if i==reverse
    fprintf('Number is palindrome. %d\n',reverse);
 end
end

Answer 4

[Jan]

A vectorized version of Roger's method:

n = 8549;
d = 10 .^ (0:floor(log10(n)));   % [1 10, 100, 1000]
v = rem(floor(n ./ d), 10);      % The vector of digits
r = v * flip(d).'                % Vector multiplication with [1000, 100, 10, 1]

Answer 5

[José-Luis]

A vectorized, faster alternative

For integers:

 your_answer = flipud(sscanf(fliplr(sprintf('%d ',a)),'%d '));

And floating point:

 your_answer = flipud(sscanf(fliplr(sprintf('%f ',a)),'%f '));

Example:

 a=randi(115422,10000,1);
 your_val = flipud(sscanf(fliplr(sprintf('%d ',a)),'%d '));

Answer 6

[Jessica]

what if you aren't allowed to use any string variables, string related function, digitrevorder() and fliplr()??

[Andrew Reibold]

Then you can do divide by 10 tricks with rounding to save each digit, then rearrange after.

Answer 7

[Kunal Kabi]

Here is your answer

clc;

clear all;

close all;

num=input('Enter a number:');

num1=num;

reverse=0;

while num1 > 0

     t = mod(num1,10);

     reverse = 10*reverse+t;

     num1 = (num1-t)/10;

   end

reverse

num

if num==reverse

    disp('Number is palindrome.');

else

    disp('Number is not palindrome');

end

Answer 8

[ANIRUDDHA]

1. Using function statement, find out the sum of the inverse of any two numbers, a, b. Choose any value of a and b to run program?

[Walter Roberson]

This does not appear to be an answer to the question that was asked.