how can I make in Simulink ∫ dt?

Hi, how can I make in Simulink ∫ dt? In time domain, not Laplace domain.
Thank you:)

Respuestas (1)

Andreas Goser
Andreas Goser el 14 de Dic. de 2012
Editada: Andreas Goser el 14 de Dic. de 2012

0 votos

The whole concept of Simulink is time based simulation. You might be confused by the look of the blocks and the transfer functions are displayed like 1/s or 1/s-1 etc.
So just use the integrator block and you are fine.

5 comentarios

ionut
ionut el 14 de Dic. de 2012
I know that I can use 1/s but my teacher told me to not use 1/s. He said to me that I can find ∫ dt in Simulink Lybrary Browser. I have to simulate a DC motor. And one of blocks is (1/La)*∫ dt. Where La is known. Could you help me please?:)
Andreas Goser
Andreas Goser el 14 de Dic. de 2012
I can't help with that. I can only speculate what your teacher might think. There are blocks that display the integral symbol, like the "Integrator Limited" block. You need to ask the teacher.
ionut
ionut el 14 de Dic. de 2012
I asked today him and I can remember that he told me that I can replace 1/s with a MUX+I can't remember what other blocks. It's that possible?
Andreas Goser
Andreas Goser el 18 de Dic. de 2012
I do not see any relationship between an integral operation and a signal infrastructure block. This is very confusing. Probably both of you call into Technical Support to sort out things together?
ionut
ionut el 22 de Dic. de 2012
I spoke with my teacher and I'll use the 1/s block. Thank you very much for you support.

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