Borrar filtros
Borrar filtros

Problem on integral and ploting...

2 visualizaciones (últimos 30 días)
ZhiH
ZhiH el 17 de Dic. de 2012
Hello there!
I do have a problem with symbolic integration. The original code looks like this:
function f = fmbloss(phi)
n1 = 1.491;
n2 = 1.405;
ns1 = n1*n1;
ns2 = n2*n2;
lambda = 0.58e-6;
ra1 = 0.5e-3;
kw = 2*pi/lambda;
bend_r = 10e-3;
thetac = acos(n2/n1);
rad = @(theta) (bend_r+ra1)*n1./(n2*cos(theta));
n1_phi = @(theta) (sqrt(ns1-ns1*cos(theta).*cos(theta)));
n2_phi = @(theta) (sqrt(ns1*cos(theta).*cos(theta)-ns2));
p = @(theta) (rad(theta)/(bend_r+ra1));
ps = @(theta) (p(theta).*p(theta));
ps1 = @(theta) (sqrt(ps(theta)-1));
log_p = @(theta) (log(p(theta)+ps1(theta)));
abs_t = @(theta) (4*n1_phi(theta).*n2_phi(theta)/(ns1-ns2));
expf = @(theta) (-2*kw*ra1*n1*cos(theta).*(log_p(theta)-ps1(theta)./p(theta)));
bt = @(theta) (abs_t(theta).*expf(theta));
sub_sin = @(theta) (sqrt(sin(theta).*sin(theta)-sin(thetac)*sin(thetac)));
sub_sins = @(theta) (sin(theta)+sub_sin(theta).*sub_sin(theta));
bt1 = @(theta) (4*sin(theta).*sub_sin(theta)./(sub_sins(theta)));
exp_f1 = @(theta) exp(-bt(theta)*phi./(2*theta));
exp_f2 = @(theta) exp(-bt(theta)*bend_r*phi.*theta/(4*ra1));
exp_f3 = @(theta) exp(-bt1(theta)*bend_r*phi/(4*ra1));
fun1 = @(theta) (exp_f1(theta));
fun2 = @(theta) (exp_f2(theta));
fun3 = @(theta) (exp_f3(theta));
theta_max = sqrt(2*ra1/bend_r);
int1 = quadl(fun1,0,theta_max);
int2 = quadl(fun2,theta_max,thetac);
int3 = quadl(fun3,thetac,pi/2);
f = pi*(int1+int2+int3)/2;
and input fmbloss(pi/3) in the command window firstly,
and error message:
>> fmbloss(pi/3)
Warning: Infinite or Not-a-Number function value encountered.
> In quadl at 105
In fmbloss at 40
Warning: Infinite or Not-a-Number function value encountered.
> In quadl at 105
In fmbloss at 41
ans =
Inf
input fmbloss(0) in the command window secondly,
>> fmbloss(0) ans = 2.467401100272340
It is not working at all.I hope someone can give me a good advise, how to deal with that. Thank you!
  1 comentario
Walter Roberson
Walter Roberson el 17 de Dic. de 2012
Your routine contains no symbolic integration ?
You are hitting infinity in your integration. You should learn how to use the debugger to figure out why. In particular,
dbstop if naninf

Iniciar sesión para comentar.

Respuestas (0)

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by