how to find out the cell array size in for loop with conditions?

I had a cell array size 60*48 and each cell having one value( 1 or less than ), then In a for loop of 1:48 , I want to know in each step the length of cell array or nukber of rows when cell array values is equal to 1.

[Arthur Roué]

I'm not sure to understand. Can you share some code ? Do you want to know the size of each element in your cell array rows ? What is equal to 1 ?

[mukesh meharda]

In .mat file, In given cell, I want to know the numbers(count) of 1 in each column which is I am using in for loop for some calculations.

lets say for i=1:48

count(1)=40, % numbers of 1 in column 1st

count(2)=31, % numbers of 1 in column 2nd

and so on.................

Answer 1

[KSSV]

Your mat file has a cell SoC2W. This is of size 60*48. Each element is a cell. You can convert it to matrix using:

M = cell2mat(SoC2W) ; 

You matrix will be of size 60*48. So each column has 60 elements.

[mukesh meharda]

after that how can i count the nymbers where matrix value is 1 in each coulmn

[KSSV]

idx = M==1 ;
count = sum(idx) ;