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Symbolic seems to have an error

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Stephen Wilkerson
Stephen Wilkerson el 11 de Sept. de 2020
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
Two typos in my original post corrected
  2 comentarios
John D'Errico
John D'Errico el 11 de Sept. de 2020
Editada: John D'Errico el 11 de Sept. de 2020
Then why did you feel the need to post it again? Just edit your original post. Anyway, it seems like everytime you don't understand a piece of code, you declare it to be a bug.
Stephen Wilkerson
Stephen Wilkerson el 11 de Sept. de 2020
We'll do you have an answer?

Respuestas (3)

Stephen Wilkerson
Stephen Wilkerson el 11 de Sept. de 2020
Yes that's what I ended up doing.

Stephen Wilkerson
Stephen Wilkerson el 11 de Sept. de 2020
Now I'm unsure how to delete the second post?

Paul
Paul el 11 de Sept. de 2020
Editada: Paul el 12 de Sept. de 2020
The RHS of your differential equation should be 3*u.
In the frequency domain, Y(s) = H(s)*U(s). It looks like you're trying to get the step repsonse of your second order system, so U(s) = 1/s. You forgot to multiply by U(s) in your symbolic approach.
num = 3;
den = [1 2 5];
syms s
nums = poly2sym(num,s);
dens = poly2sym(conv(den,[1 0]),s); % here!
ilaplace(nums/dens)
ans =
3/5 - (3*exp(-t)*(cos(2*t) + sin(2*t)/2))/5

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