Hi, Can anyone tell me how to find average of three successive values in matlab, i have an array of 200 values
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I have 200 values and need to find average of three successive values in complete array
1 comentario
Image Analyst
el 9 de Feb. de 2013
Which three?
Respuestas (2)
Azzi Abdelmalek
el 9 de Feb. de 2013
Editada: Azzi Abdelmalek
el 9 de Feb. de 2013
x=rand(201,1);
m=mod(numel(x),3)
if m>0
x(end+1:end+3-m)=mean(x(end-m+1:end))
end
out=mean(reshape(x,3,[]))
your_vals = randi(100,1,200);
filterLength = 3;
%One option
your_result_1 = conv(your_vals,ones(1,filterLength)./filterLength);
your_result_1 = your_result_1(filterLength:end-filterLength+1); %Getting rid of the tails
%Alternatively
your_result_2 = filter(ones(1,filterLength)./filterLength,1,your_vals);
your_result_2(1:filterLength-1) = []; %Getting rid of the tails
%One more still
your_result_3 = arrayfun(@(x) mean( your_vals(x:x+filterLength-1) ), 1:numel(your_vals) - filterLength + 1); %one liner
%Rounding up
your_result_4 = mean(cell2mat(arrayfun(@(x) circshift(your_vals,[0 -x]),(0:filterLength-1)','uniformoutput',false)));
your_result_4 = your_result_4(1:end-filterLength+1); %Getting rid of the tails
Plus many others
2 comentarios
Image Analyst
el 9 de Feb. de 2013
Editada: Image Analyst
el 9 de Feb. de 2013
I hate it when people don't put enough information into their question so it causes us to have to guess at multiple possible meanings and come up with multiple possible solutions. By the way, with your conv() solution, there are boundary effect options of 'same' and 'valid' to handle "getting rid of tails" internally.
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