??? Index exceeds matrix dimensions. please help me

 [m n]=size(handles.data1);%menentukan ukuran citra

    for o=1:m
    for p=1:n
        if o<0 
      o=1;     
    end
    if p<0 
      p=1;     
    end
    [d c l]=size(handles.data1);
    masuk_enkripsi=double(handles.data1(p:p+d-1,o:o+c-1,:));

 ??? Index exceeds matrix dimensions.

 Error in ==> enkripsi>btn_enkripsi_Callback at 148
    masuk_enkripsi=double(handles.data1(p:p+d-1,o:o+c-1,:));

[matpan community]

it is not Using lowercase and uppercase but "the letter o < the number 0" :)

[ChristianW]

What are you trying to do in this line:

masuk_enkripsi=double(handles.data1(p:p+d-1,o:o+c-1,:));

Answer 1

[ChristianW]

With your image height d and if p gets p=2, then you are trying to address with (p+d-1) the (d+1) pixel. Thats not possible.

[matpan community]

have a solution?

[ChristianW]

Yes, I've got an infinite amount of solutions. I'll rub my crystal ball for visions regarding the purpose of your code.

Answer 2

[Jan]

It is confusing to change the loop counter of A FOR loop inside the loop.

Using lowercase and uppercase Oh's as names of variables is confusing also: "if o<0" looks funny, but is to hard to read.

I confirm, that CristianW's answer is exhaustive: Obviously either p+d-1 and/or d+1 exceed the available size. But it is impossible to guess what you want to do instead.

[matpan community]

it is not Using lowercase and uppercase but "the letter o < the number 0" :)

[Walter Roberson]

But no explanation for what you think the code should be doing??

Answer 3

[Walter Roberson]

In your line

   [m n]=size(handles.data1);%menentukan ukuran citra

you are using size() as if you expect handles.data1 to be two-dimensional. But later you have

[d c l]=size(handles.data1);

which is expecting handles.data1 to be 3 dimensional. If it is 3 dimensional then when you ask for its size() using only two outputs (e.g., [m n]) then size() will set the second output equal to the product of the second and third dimensions -- so although m would be the same as the later d, n would be the product of c and l. This is going to lead to problems when you do your looping over "n" and try to use that value as the index to the second dimension.