Getting an if statement to accept a word.

I'm writing a program to find a persons training heart rate based on a few factors and when it asks for fitness level I want the user to be able to use low, medium or high as and answer.

disp('Enter your information to find your ideal training heart rate.')
age= input('Enter your age:');
rhr= input('What is your resting heart rate:');
fit= input('Would you describe your fitness level as low, medium or high?');
if fit=='low'
  fit=0.55;
elseif fit=='medium'
  fit=0.65;
else fit=='high'
  fit=0.8;
end
thr=[(220-age)-rhr]*fit+rhr;
disp('Your ideal training heart rate is', num2str(thr))

I can get it to accept 'low' but not just low. How can I get it to accept words?

also what am i missing from my final part in order to get is to display everything?

[Mahdi]

Can you be more specific with display everything? Your code displays the thr value to me, is that what you want? Look at my answer for more information.

Answer 1

[Azzi Abdelmalek]

disp('Enter your information to find your ideal training heart rate.')
age= input('Enter your age:');
rhr= input('What is your resting heart rate:');
fit= input('Would you describe your fitness level as low, medium or high?');
id=listdlg('PromptString','make your choice',...
              'SelectionMode','single',...
              'ListString',{'low','medium','high'})
if id==1
  fit=0.55;
elseif id==2
  fit=0.65;
else 
  fit=0.8;
end
thr=[(220-age)-rhr]*fit+rhr;
disp('Your ideal training heart rate is', num2str(thr))

Answer 2

[Mahdi]

Just change your inputs function to be:

fit=input('Would you describe your fitness level as low, medium, or high?', 's')

The 's' at the end tells MATLAB it's a string, so now you can input low as an answer.

You should use the strcmp() function when comparing strings.

So, in your case, using the first example,

if strcmp(fit, 'low')==1
...
end

You might want to look at strncmp as well. You still need to put the quotations though.

Make sure to use elseif fit=='high' as well in that line. (or just else on its own)