How do I write something to run this function?

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WARRIOR24
WARRIOR24 el 14 de Dic. de 2020
Editada: Rik el 14 de Dic. de 2020
I am relativitly new to MATLAB. Most of my new learnings have been learning how to write and run BASIC Functions. I downloaded this CRC32 bit function from File Exchange and I am having a hard time to run/callout the function.
I am trying to enter a HEX number and return the CRC Calculation in HEX.'
I am trying to calculate the CRC for something like "00060D00"
function crc = crc32(data)
%crc32 Computes the CRC-32 checksum value of a byte vector.
%--------------------------------------------------------------------------
% CRC = crc32(DATA) computes the CRC-32 checksum value of the data stored
% in vector DATA. The elements of DATA are interpreted as unsigned bytes
% (uint8). The result is an unsigned 32-bit integer (uint32). Polynomial
% bit positions have been reversed, and the algorithm modified, in order
% to improve performance.
% Version: 1.00
% Programmer: Costas Vlachos
% Date: 23-Dec-2014
% Initialize variables
crc = uint32(hex2dec('FFFFFFFF'));
poly = uint32(hex2dec('EDB88320'));
data = uint8(data);
% Compute CRC-32 value
for i = 1:length(data)
crc = bitxor(crc,uint32(data(i)));
for j = 1:8
mask = bitcmp(bitand(crc,uint32(1)));
if mask == intmax('uint32'), mask = 0; else mask = mask+1; end
crc = bitxor(bitshift(crc,-1),bitand(poly,mask));
end
end
crc = bitcmp(crc);
I saved it a new folder and path with nothing in there except this function (crc32.m)
When I click "Run" directly in the "Script" Tab/Window, this is what I get in the Command Window:
>> crc32
Not enough input arguments.
Error in crc32 (line 16)
data = uint8(data);
And takes me to the "Run" and shows this:
Can some explain this to me as well as how to call and use this function? Write a code? What I need to do to run and execute this funtion? How to enter?
  2 comentarios
Walter Roberson
Walter Roberson el 14 de Dic. de 2020
I am trying to calculate the CRC for something like "00060D00"
When you run the function by name, what is your expectation of where matlab will search to figure out that it is 00060D00 that it is to operate on this run?
WARRIOR24
WARRIOR24 el 14 de Dic. de 2020
Editada: WARRIOR24 el 14 de Dic. de 2020
I believe:
>> data=[00060D00];

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KALYAN ACHARJYA
KALYAN ACHARJYA el 14 de Dic. de 2020
Editada: KALYAN ACHARJYA el 14 de Dic. de 2020
crc32(data);
%......^??
You have to pass the input arguments (data) as mentioned in the function code. e.g.
>>data=[1:18]; % Pass the appropriate data type as per function defined??
>>crc32(data)
  8 comentarios
WARRIOR24
WARRIOR24 el 14 de Dic. de 2020
Thank you guys,
I have another question, later and it might along the lines of entering multiple inputs all at once:
"0000F0F03"
"AFCED902"
"['000F0990','00002020']"
Idk if that is possible to enter all at once. But the last input has me stopped now and if it is possible to enter that kind of entry.
Rik
Rik el 14 de Dic. de 2020
Editada: Rik el 14 de Dic. de 2020
As Walter mentioned: dec2hex will convert the value to hexadecimal without any issues.
dec2hex(crc32(data))
The function you showed doesn't handle array inputs by default, so you will have to use a loop to process your inputs one by one. It is also possible to use arrayfun to hide the loop.

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