Apply a matrix to a function
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Johnny Yoon
el 7 de En. de 2021
Comentada: Johnny Yoon
el 25 de En. de 2021
Dear Matlab experts,
I would like to apply a matrix into a function as follows.
clear all;
sizee = 1000;
syms 'T' [1 sizee]
T_syms = sym('T', [1 sizee]);
f = sym(zeros(sizee, sizee));
f(:,:) = T1 + T2 + T3 + T4 + ... + T1000; % This is just to make sample equations.
x_vars = (1:1000);
f_ftn (T_syms) = f;
solution = f_ftn(x_vars);
However, I got an error "Symbolic function expected 1000 input arguments but received 1." So, it seems I can't apply a matrix directly to a function. Is there any way that a matrix can be applied to a function? I can use matlabFunction as follows. However, it takes a way too long, like hours. Is there any way which takes a shorter amount of time? Thank you.
f_ftn02 = matlabFunction(f, 'Vars', {T_syms});
solution = f_ftn02(x_vars);
2 comentarios
Walter Roberson
el 22 de En. de 2021
f_ftn02 = matlabFunction(f, 'Vars', {T_syms});
is the way. You could experiment, though, with
f_ftn02 = matlabFunction(f, 'Vars', {T_syms}, 'optimize', false);
As you are not writing to a file, I do not expect it to make any difference, but I saw a recent hint somewhere that some optimization is maybe now being done even when not writing to files, so you could try
Respuesta aceptada
Deepak Meena
el 22 de En. de 2021
Editada: Deepak Meena
el 22 de En. de 2021
Hi Johnny,
As far as my understanding goes , it is not possible. Because when you create a symbolic function indexed with a list of syms , the MATLAB will consider it as single entity.
But you can do something like this
clear all;
sizee = 1000;
syms 'T' [1 sizee]
T_syms = sym('T', [1 sizee]);
f = sym(zeros(sizee, sizee));
f(:,:) = T1 + T2 + T3 + T4 + ... + T1000; //or use sum(T_syms)
x_vars = (1:1000);
H(T_syms) = f;
cells = num2cell(x_vars);
H(cells{:});
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