Borrar filtros
Borrar filtros

Inverse of a covariance matrix (loop)

1 visualización (últimos 30 días)
Kevin van Berkel
Kevin van Berkel el 23 de Abr. de 2013
Hi all,
I am stuck to create a loop which yields inverse of covariance matrices.
Data description:
I have the returns of three risky assets: mkt, hml and mom, from nov 3, 1926 up to dec 31, 2012.
For each year (so starting from Nov 3, 1927)I want the inverse covariance matrix for the three risky assets.
The dates are described (thanks Andrei) by the following code:
d = [19261103; 20121231];
ddte = datenum(num2str(d),'yyyymmdd');
ndte = (ddte(1):ddte(2))';
t = weekday(ndte);
ndte = ndte(t ~= 1 & t ~= 7);
yourdata = [date,mkt,hml,mom];
[yy,mm,dd] = datevec(yourdata(:,1));
ymd = [yy,mm,dd];
im = mm == 11 & dd >= 3;
ii = strfind([~im(1),im(:)'],[0 1]);
So I am stuck what do I have to add to retrieve the inverse covariance matrices per year.
Hopefully someone can help me out.
Thanks!

Respuestas (1)

Kevin van Berkel
Kevin van Berkel el 23 de Abr. de 2013
I adjusted the code with cov in it, but it does not yield the desired results:
d = [19261103; 20121231];
ddte = datenum(num2str(d),'yyyymmdd');
ndte = (ddte(1):ddte(2))';
t = weekday(ndte);
ndte = ndte(t ~= 1 & t ~= 7);
yourdata = [date,mkt,hml,mom];
[yy,mm,dd] = datevec(yourdata(:,1));
ymd = [yy,mm,dd];
im = mm == 11 & dd >= 3;
ii = strfind([~im(1),im(:)'],[0 1]);
sb = zeros(numel(ndte),1);
sb(ii) = 1;
sbc = cumsum(sb);
t = sbc > 0 & sbc ~= max(sbc);
sbb = sbc(t);
sb1 = find(sb(t));
wdta = yourdata(t,:);
[r, c] = ndgrid(sbb,1:size(wdta,2)-1);
out1 = accumarray([r(:) c(:)],reshape(wdta(:,2:4),[],1),[],@cov);
out = [ymd(ii(1:end-1),:),out1] ;
What do I do wrong?

Categorías

Más información sobre Introduction to Installation and Licensing en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by