Loop for nested matrix multiplication

9 visualizaciones (últimos 30 días)
Kevin van Berkel
Kevin van Berkel el 27 de Abr. de 2013
Hello guys,
My problem is the following.
I have two matrices: a 155*3 matrix and a 465*3 matrix. I have to multiply each 1x3 row (from the 155*3 matrix) with each consecutive 3x3 matrix from the 465*3 matrix.
Now the loop I tried did not work out and I just can't get my thought's around it.
Here's my code:
m = size(A,2);
n = B(D:E);
D = B(1,:);
E = B(1:3,:);
C = zeros(m,n);
for ii = 1:m
for jj = 1:n
C(ii,jj) = sum(A(ii,:).*B(:,jj).');
end
end
Where matrix A is the 155*3 matrix and matrix B is the 465*3 matrix.
Any suggestions how to adjust the loop?
Thanks a million.
Kevin
  2 comentarios
the cyclist
the cyclist el 27 de Abr. de 2013
This code will not get past the line
n = B(D:E)
unless D and E were already define previously. Can you post the entire code?
What do you want the shape of the final output to be? 155*3?
Is this a school assignment?
Kevin van Berkel
Kevin van Berkel el 27 de Abr. de 2013
Hi Cyclist,
thank you for your response.
I tried to define D and E as integers but did not work out.
my code looks like this now:
d = [19261103; 20121231];
ddte = datenum(num2str(d),'yyyymmdd');
ndte = (ddte(1):ddte(2))';
t = weekday(ndte);
ndte = ndte(t ~= 1 & t ~= 7);
yourdata = [date,mkt,hml,mom];
[yy,mm,dd] = datevec(yourdata(:,1));
ymd = [yy,mm,dd];
im = mm == 11 & dd >= 3;
ii = strfind([~im(1),im(:)'],[0 1]);
sb = zeros(numel(ndte),1);
sb(ii) = 1;
sbc = cumsum(sb);
t = sbc > 0 & sbc ~= max(sbc);
sbb = sbc(t);
sb1 = find(sb(t));
wdta = yourdata(t,:);
[r, c] = ndgrid(sbb,1:size(wdta,2)-1);
out1 = accumarray([r(:) c(:)],reshape(wdta(:,2:4),[],1),[],@mean);
means = [ymd(ii(1:end-1),:),out1] ;
d = [19261103; 20121231];
ddte = datenum(num2str(d),'yyyymmdd');
ndte = (ddte(1):ddte(2))';
t = weekday(ndte);
ndte = ndte(t ~= 1 & t ~= 7);
yourdata = [date,mkt,hml,mom];
[yy,mm,dd] = datevec(yourdata(:,1));
ymd = [yy,mm,dd];
im = mm == 11 & dd >= 3;
ii = strfind([~im(1),im(:)'],[0 1]);
sb = zeros(size(yourdata,1),1);
sb(ii) = 1;
sbc = cumsum(sb);
t = sbc > 0 & sbc ~= max(sbc);
sb1 = diff(find([sb(t);1]));
wdta = yourdata(t,:);
s = size(wdta,2) - 1;
ydcell = mat2cell(wdta(:,2:end),sb1,s);
invcov = cellfun(@(x)cov(x)\eye(s),ydcell,'un',0);
*m = size(A,2);
D = B(1,:);
E = B(1:3,:);
n = B(D:E);
C = zeros(m,n);
for ii = 1:m
for jj = 1:n
C(ii,jj) = sum(B(ii,:).*A(:,jj).');
end
end*
Where the latter part is where I got stuck.
This is no school assignment but I need to determine portfolio weights to do further research. I am quite new to matlab so still have to get familiar with certain parts of it..
Thanks anyway for your help!
The final shape should indeed be 155*3!

Iniciar sesión para comentar.

Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 28 de Abr. de 2013
eg:
A = randi(4,155,3);
B = randi(8,455,3);% your matrices A and B
one variant;
s = size(A);
C = zeros(s);
for j1 = 1:s(1)
C(j1,:) = A(j1,:)*B((j1-1)*s(2)+1:j1*s(2),:);
end
other variant
s = size(A);
C = zeros(s);
for j1 = 1:s(1)
C(j1,:) = B((j1-1)*s(2)+1:j1*s(2),:)*A(j1,:)';
end

Más respuestas (4)

Matt J
Matt J el 27 de Abr. de 2013
Editada: Matt J el 27 de Abr. de 2013
Here's a way with very short loops, using my DOWNSAMPN utility below
a=reshape(A.',[],1);
C=bsxfun(@times,a,B);
C=downsampn(C,[3,1]);
function M=downsampn(M,bindims)
%DOWNSAMPN - simple tool for downsampling n-dimensional nonsparse arrays
%
% M=downsampn(M,bindims)
%
%in:
%
% M: an array
% bindims: a vector of integer binning dimensions
%
%out:
%
% M: the downsized array
nn=length(bindims);
[sz{1:nn}]=size(M); %M is the original array
sz=[sz{:}];
newdims=sz./bindims;
args=num2cell([bindims;newdims]);
M=reshape(M,args{:});
for ii=1:nn
M=mean(M,2*ii-1);
end
M=reshape(M,newdims);
  2 comentarios
Matt J
Matt J el 28 de Abr. de 2013
Kevin van Berkel Commented:
Hello Matt,
Thank you for your response.
I tried your code but Matlab yields some errors. The first error is that the
function M=downsampn(M,bindims) is wrong. Matlab does not know what to do with the "function" part. The next error I get is:
Error using bsxfun Non-singleton dimensions of the two input arrays must match each other.
Error in mult (line 2) C=bsxfun(@times,a,B);.
Do you have any clue how to resolve this?
Cheers.
Matt J
Matt J el 28 de Abr. de 2013
Editada: Matt J el 28 de Abr. de 2013
function M=downsampn(M,bindims) is wrong. Matlab does not know what to do with the "function" part.
You were supposed to put the code for downsampn in its own mfile. If that's not the problem, I need to see copy/pastes of the error messages.
Error using bsxfun Non-singleton dimensions of the two input arrays must match each other.
I don't receive this error. In all likelihood, it means that A is not 155x3 or B is not 465x3 like you posted. Here is the output of WHOS when I run. You should examine your matrix sizes in a similar way.
>> whos
Name Size Bytes Class Attributes
A 155x3 3720 double
B 465x3 11160 double
C 155x3 3720 double
a 465x1 3720 double

Iniciar sesión para comentar.


Kevin van Berkel
Kevin van Berkel el 28 de Abr. de 2013
Editada: Matt J el 28 de Abr. de 2013
Relocated to Comment by Matt J

Kevin van Berkel
Kevin van Berkel el 29 de Abr. de 2013
Hello Matt, thanks for your effort but Andrei's solution is more suitable to me.
Andrei, thanks again, got it running perfectly now.

Matt J
Matt J el 29 de Abr. de 2013
Editada: Matt J el 29 de Abr. de 2013
Another loopless way. Note that it would all be much simpler/faster (i.e., no transposes) if the data were organized in columns instead of rows
Ar=reshape(A.',1,3,[]);
Br=reshape(B.',3,3,[]);
Cr=sum(bsxfun(@times,Ar,Br),2);
C=squeeze(Cr);
One could also use FEX: mtimes for part of the above
Cr=mtimesx(Ar,Br,'t');

Categorías

Más información sobre Logical en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by