Finding numChanges in array
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Olivia Gilliam
el 16 de Feb. de 2021
Editada: Daniel Pollard
el 16 de Feb. de 2021
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/521367/image.png)
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i'm trying to write a code that calculates the number of changes in V. There should be 6. (V = [1, 1, 1, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1];) However, the code I wrote spits out 18.
This is what I have-
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/521377/image.png)
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Daniel Pollard
el 16 de Feb. de 2021
Editada: Daniel Pollard
el 16 de Feb. de 2021
Replace
for i=1;length(V)
with
for ii = 1:length(V)
The semicolon -> colon is a typo I suspect, and i has a built in value so it's a bad idea to use it as a variable. Right now, your code runs for i=1, displays length(V) (which is 18) and does nothing else.
The line
numChanges + = 1
will fail when it reaches it. Replace it with
numChanges = numChanges + 1;
which won't fail.
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