While loop for testing the end of vector (Matlab)
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Afluo Raoual
el 17 de Feb. de 2021
Comentada: Afluo Raoual
el 17 de Feb. de 2021
Dear members,
If we have a long vector that we don't know its length, and we want use while loop to repeat the task than stop and exit from the loop when the vector length is at its end.
For example, if the vector length is 10000 bits so we repeat the calculation (of any task) until 10000 than we stop and exit.
But in my case, I don't know the length of my vector. So how can I program this please?
Thank you.
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Rik
el 17 de Feb. de 2021
You can use numel to create a loop over a vector of unknown size:
A=rand(1,100);
for n=1:numel(A) % n will go to 100
%your code here
end
5 comentarios
Rik
el 17 de Feb. de 2021
You're welcome. If either answer solved your issue, please consider marking it as accepted answer. If you feel both answers solved your issue, pick the best one and give the other an upvote.
If your issue is not yet resolved, feel free to comment with your remaining issues.
Más respuestas (1)
Daniel Pollard
el 17 de Feb. de 2021
Editada: Daniel Pollard
el 17 de Feb. de 2021
If you know that it's 1-dimensional, you can use
numel(vector)
which returns the length of your vector. Also useful to know is
size
which returns the size of a matrix (eg, [2 2] for a 2x2 matrix, [10 1] for a 10x1 vector, etc).
Edit I've replaced length with numel - thank you Rik.
3 comentarios
Daniel Pollard
el 17 de Feb. de 2021
This is news to me - I've used length multiple times without any issues. What exactly is the bug?
Rik
el 17 de Feb. de 2021
The bug is not with length, the bug is with the use of length. For a vector it is equivalent to numel, and for array inputs it is probably not what you mean. How often did you want to loop over max(size(A)) without knowing which dimension is that maximum?
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