Finding a bit value ?
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Hi. I have a value like a = 10101 this would change after how my program is run, but i will always use 0 or 1. so i consider this binary. now i would like to get the status of bit 5 i.e the first number (closest to the equal sign).
note!: the intention is to have the binary row decied which buttons are displayed in a gui.
this is what i have come up with
%code
for i = 0:4
count = i+1
if (bitget(main_sel2, count)==1)
set(handles.(sprintf('but%d', count))(:),'Visible','on');
else
set(handles.(sprintf('but%d', count))(:),'Visible','off');
end
end
1 comentario
Respuestas (1)
Matt J
el 22 de Mayo de 2013
Editada: Matt J
el 22 de Mayo de 2013
One way,
>> bits=fliplr(num2str(a)-'0'); bits(5)
ans =
1
4 comentarios
Matt J
el 25 de Mayo de 2013
FLIPLR isn't doing anything significant. You posted that you want the indexing order of the bits to run from right to left (bit #5 is the leftmost bit). If you omit FLIPLR, you will be reading from left to right instead.
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