While loop for the elements of an array

I have an array:
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
I want to make a while loop that does the following
enas=0;
while a(i)==1 %
enas=enas+1;
end
But I don't know how to express it in matlab. Can you help me please?

1 comentario

Image Analyst
Image Analyst el 27 de Mayo de 2013
It's recommended not to use i (the imaginary variable) as a variable name.

Iniciar sesión para comentar.

 Respuesta aceptada

Image Analyst
Image Analyst el 27 de Mayo de 2013
Here's how you'd do it:
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
enas=0;
k = 1;
while a(k)==1 %
enas=enas+1
k = k + 1
end
But here's how a real MATLAB programmer would do it:
enas = find(a~=1, 1, 'first')-1

3 comentarios

Giorgos Papakonstantinou
Giorgos Papakonstantinou el 27 de Mayo de 2013
Editada: Giorgos Papakonstantinou el 27 de Mayo de 2013
Thank you Image. What if also have to count the in between ones?
If you need to count the length of each stretch of 1's in your array, and if you have the Image Processing Toolbox, you'd do this:
measurements = regionprops(a==1, 'Area');
allLengths = [measurements.Area]; % Get lengths of all stretches of 1s.
If you don't have the Image Processing Toolbox, it's more difficult - let me know if you have that unfortunate case.
Unfortunately I don't. I just do:
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
enas = find(a~=1)-1
segments=zeros(length(enas),1);
segments(1,1)=enas(1);
segments(2:end,1)=diff(enas)-1;
segments
which a bit complicated but it does the job... If you have better ideas tell me. thank you!

Iniciar sesión para comentar.

Más respuestas (1)

Jason Nicholson
Jason Nicholson el 27 de Mayo de 2013
See the lines below. This will work.
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
i = 1;
enas=0;
while a(i)==1 %
enas=enas+1;
i = i +1;
end

4 comentarios

Giorgos Papakonstantinou
Giorgos Papakonstantinou el 27 de Mayo de 2013
thank you Jason!
Giorgos Papakonstantinou
Giorgos Papakonstantinou el 27 de Mayo de 2013
I would like to count the ones in between. How I can I do that? In this example it would be 7 6 4.
Matt Kindig
Matt Kindig el 27 de Mayo de 2013
Editada: Matt Kindig el 27 de Mayo de 2013
This should do it:
b = [0, a, 0]; %ensure that ends are not 1
edges = find(b~=1); %location elements that are not 1
spans = diff(edges)-1; %distance between edges is span of 1's
enas = spans(spans~=0) %should output 7 6 4
Suppose that I want find the edges of ones and of not ones. Suppose the array is:
a=[1 1 1 1 1 1 12 10 1 1 1 1 1 11 12 1 1 1 2 3]
a(1:6) -->area1 of ones
a(7:8) -->area1 of not ones
a(9:a13) -->area2 of ones
a(14:15)-->area2 of not ones
a(16:19)-->area3 of ones
a(20) -->area3 of not ones
and so on..

Iniciar sesión para comentar.

Categorías

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by