Borrar filtros
Borrar filtros

Splitting up values from variables

1 visualización (últimos 30 días)
Frank
Frank el 18 de Mayo de 2011
I've written a script that obtains the centroid of an object in my image. I store that value as a reference and calculate the difference from the other images so I can align them to the first. However the coordinates are stored in the variable "displacement" and I only want the x coordinate. Is there a way I can get it automatically?
Code
o = imread('343TESTA.tif');
p = size(o);
imtool(o);
for k = 1:p(1)
for l = 1:p(2)
if o(k,l) > 160 & o(k,l) > 160
d(k,l) = 1;
else
d(k,l) = 0;
end
end
end
imtool(d);
labela = bwlabel(d);
imagesc(labela);
[labela,num] = bwlabel(d,4);
stats = regionprops(labela,'basic');
stats(1).Area
stats(1).Centroid
max_area = max([stats.Area]);
biggrain = find([stats.Area]== max_area);
p = stats(biggrain).Centroid
%Second Image
a = imread('343TEST.tif');
b = size(a);
imtool(a);
for c = 1:b(1)
for l = 1:b(2)
if i(c,l) > 160 & a(c,l) > 160
e(c,l) = 1;
else
e(c,l) = 0;
end
end
end
imtool(e);
labelb = bwlabel(e);
imagesc(labelb);
[labelb,num] = bwlabel(e,4);
stats = regionprops(labelb,'basic');
stats(1).Area
stats(1).Centroid
max_area = max([stats.Area]);
biggrain = find([stats.Area]== max_area);
o = stats(biggrain).Centroid
%Calculates the differences in the centroid
displacement = p -o
%%IM Translate
a2 = imtranslate(a, [0 -1.0376]); %Note: [y x] for imtranslate, if it's negative make it positive
subplot(1,2,1), imshow(v)
subplot(1,2,2), imshow(u2)
imwrite(a2, '343TEST11','tif');
Output (example):
Displacement =
-1.036 -6.7288
I only want the -1.036 portion

Respuesta aceptada

Matt Fig
Matt Fig el 18 de Mayo de 2011
x = Displacement(1);
or
Displacement = Displacement(1);
  2 comentarios
Frank
Frank el 18 de Mayo de 2011
I didn't know which one to accept, they both worked :P
Frank
Frank el 18 de Mayo de 2011
Thanks!

Iniciar sesión para comentar.

Más respuestas (1)

Sean de Wolski
Sean de Wolski el 18 de Mayo de 2011
Displacement(1)
? Seems too simple to answer your question.
  2 comentarios
Matt Fig
Matt Fig el 18 de Mayo de 2011
I'll second that comment.
Frank
Frank el 18 de Mayo de 2011
Thanks!

Iniciar sesión para comentar.

Categorías

Más información sobre MATLAB en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by