How not to terminate the polyxpoly loop, when the lines don't intersect?

V=1;
while V<=21
[xx12(V),yy12(V)] = polyxpoly([x01 x1(V)],[y01 y1(V)],[x02 x2(V)],[y02 y2(V)]);
plot(xx12(V),yy12(V),'o'); axis([-80 80 -10 100]);
pause(1);
V=V+1;
end

Hello. I have a code in which I mark the intersection point of two different lines every second. The loop works fine, but only until the lines actually intersect. For example, when they are parallel, an error 'Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.' occurs, and the loop stops running.

Is there any way, that in this case the loop doesn't terminate, but continues to the next iteration?

Answer 1

[darova]

What about if..else statement?

[x,y] = polyxpoly(...);
if ~isempty(x)
    % code
end

[Lukasz Zaczek]

The error occurs during the calculation of the polyxpoly function, so the loop placed later doesn't change anything, because if there is an error, it won't even start.

[Lukasz Zaczek]

Ok, It worked after a few adjustments, thank you.

[darova]

you are welcome