How do i reconstruct a matrix???
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George
el 21 de Jun. de 2013
Respondida: George
el 14 de Oct. de 2013
I have a matrix 2000x3 like this:
1 1 6
1 2 8
1 3 15
....
2 1 10
2 2 20
2 3 13
....
3 1 12
3 2 18
3 3 14
...
...
and i want to reconstruct like this:
1 1 6
1 2 8
1 3 15
....
2 3 13
2 2 20
2 1 10
....
3 1 12
3 2 18
3 3 14
...
...
Please help me..
3 comentarios
Image Analyst
el 24 de Jun. de 2013
Editada: Image Analyst
el 24 de Jun. de 2013
The middle group has the second column flipped. But that's not enough to figure out what needs to be done in general. And what does this have to do with Image Processing, like the tag says?
Respuesta aceptada
Andrei Bobrov
el 25 de Jun. de 2013
a - your array
a1 = a;
n = unique(a(:,1));
for jj = 1:numel(n)
if rem(n(jj),2) == 0
t = a1(:,1) == n(jj);
a1(t,:) = flipud(a1(t,:));
end
end
Más respuestas (2)
Evan
el 24 de Jun. de 2013
M(:,:,2) = flipud(M(:,:,2))
As an example:
M = rand(3,3,3); %random example 3d matrix
M(:,:,2) = flipud(M(:,:,2));
1 comentario
Evan
el 26 de Jun. de 2013
In light of George's update in the below comment, this code does not do what he is asking for. http://www.mathworks.com/matlabcentral/answers/79846#comment_156778
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