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How to solve "Index exceeds matrix dimensions" error?

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noor shahida
noor shahida el 24 de Jun. de 2013
Comentada: Jan el 23 de Oct. de 2017
Hi all.. I have a coding here..which is when i run it appear "Index exceeds matrix dimensions".Can anyone help.
NumBasei = 1;
for NBi = 1:InnerRings-1;
NumBasei = NumBasei + 6*NBi;
end
B_dist = sqrt(B_x.^2 + B_y.^2);
Bdata = [B_dist' B_x' B_y' B_l']; % distance % x % y % label
Bdata_s = sortrows(Bdata);
Bdata_in = Bdata_s(1:NumBasei , :);
scatter(Bdata_in(:,2)',Bdata_in(:,3)',20,'filled','w');
thanks.
  2 comentarios
Jan
Jan el 24 de Jun. de 2013
Please post the complete error message and mention in which line the error occurs. We cannot run your function, because we do not have your data.
noor shahida
noor shahida el 24 de Jun. de 2013
error come from Bdata_in = Bdata_s(1:NumBasei , :);
NumBase = length(B_x); for BC = 1:NumBase; Bx = B_x(1,BC); By = B_y(1,BC); if draw_bounds==1; line([Bx-R*cosd(60) Bx+R*cosd(60) Bx+R Bx+R*cosd(60) Bx-R*cosd(60)... Bx-R Bx-R*cosd(60)],[By+R*sind(60) By+R*sind(60) ... By By-R*sind(60) By-R*sind(60) By By+R*sind(60)]); hold on end fnb = floor(NumBase/4); if (BC == fnb)||(BC==2*fnb)||(BC==3*fnb); end scatter(Bx,By,70,'filled');
end
NumBasei = 1; for NBi = 1:InnerRings-1; NumBasei = NumBasei + 6*NBi; end B_dist = sqrt(B_x.^2 + B_y.^2); Bdata = [B_dist' B_x' B_y' B_l']; % distance % x % y % label Bdata_s = sortrows(Bdata); Bdata_in = Bdata_s(1:NumBasei , :); scatter(Bdata_in(:,2)',Bdata_in(:,3)',20,'filled','w');

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Respuestas (5)

Jan
Jan el 24 de Jun. de 2013
You can use the debugger to find out more details:
dbstop if error
Then start the program again. It stops, when the error occurs. Then you can inspect the indices and the available dimensions.
  3 comentarios
noor shahida
noor shahida el 24 de Jun. de 2013
ihave try it,but still error at the same place.
Jan
Jan el 24 de Jun. de 2013
Of course the error appears in the same place. This is the nature of a debugger. But now you can check the size of the locally used variables and find out, why Bdata_s has les than NumBasei rows.

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Hugo
Hugo el 24 de Jun. de 2013
At first glance, the error should appear as a consequence of the line
Bdata_in = Bdata_s(1:NumBasei , :);
So, I would recommend you to compare the value of "NumBasei" with the number of rows in Bdata_s. If NumBasei is greater than size(Bdata_s,1), then you should do something about it.

poongothai rajan
poongothai rajan el 30 de Mayo de 2014
[rows, cols, numOfBands] = size(T); % totalPixelsOfImage = rows*cols*numOfBands; image = rgb2hsv(T);
% split image into h, s & v planes h = image(:, :, 1); s = image(:, :, 2); v = image(:, :, 3);
I have a coding here..which is when i run it appear "Index exceeds matrix dimensions".Can anyone help.

poongothai rajan
poongothai rajan el 30 de Mayo de 2014
I have a coding here..which is when i run it appear "Index exceeds matrix dimensions".Can anyone help.
[rows, cols, numOfBands] = size(T);% totalPixelsOfImage = rows*cols*numOfBands; image = rgb2hsv(T);(T is the training database)
% split image into h, s & v planes
h = image(:, :, 1);
s = image(:, :, 2);
v = image(:, :, 3);

Nikhil Shrestha
Nikhil Shrestha el 23 de Oct. de 2017
Editada: Walter Roberson el 23 de Oct. de 2017
openExample('images/BoostLocalColorContrastUsingColorModeExample')
Index exceeds matrix dimensions.
Error in openExample>readMetadata (line 95)
metadata.component = tokens{1};
Error in openExample (line 10)
metadata = readMetadata(id);
  3 comentarios
Walter Roberson
Walter Roberson el 23 de Oct. de 2017
Which MATLAB version are you using?
What shows up for
which -all openExample
You would expect to see only toolbox/matlab/helptools/openExample.m . In R2017b, openExample.m does not have code corresponding to the error message you show.
Jan
Jan el 23 de Oct. de 2017
@Nikhil Shrestha: Please open a new thread for a new question. If you only hijack another thread, you cannot accept an answer, but cause confusion, because it is not longer clear to which question an answer belongs to. After creating a new question, p0lease remove this "pseudo-answer"- Thanks.

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