Matrix line by line

how can i go through a matrix line by line?

I have this matrix and would like to have the value of a spinner depending on the value.

x = [1:1:5; 6:1:10]

Answer 1

[Walter Roberson]

x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nrow = size(x,1);

for K = 1 : 5
   spin = randi(nrow);
   randrow = x(spin,:)
end

randrow = 1×5

11 12 13 14 15

randrow = 1×5

26 27 28 29 30

randrow = 1×5

26 27 28 29 30

randrow = 1×5

11 12 13 14 15

randrow = 1×5

31 32 33 34 35

[TheDice]

ok maybe i didn't write that correctly. when i enter 6 in my spinner i want the value from the second line in the first column.

if I query the so x(6) I get yes the value from the second row third column

[Walter Roberson]

It sounds like you want linear indexing, but row by row

x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nent = numel(x);

xt = x.';

for K = 1 : 5
   spin = randi(nent);
   randval = xt(spin);
   [spin, randval]
end

ans = 1×2

1 1

ans = 1×2

37 0

ans = 1×2

19 19

ans = 1×2

35 35

ans = 1×2

30 30

The entries in the array happen to all be equal to their index when operating with that scheme, except for the last few, and you can see in my example that indeed it happened to pull out the stored value (0) at index 37

[TheDice]

Thank you. Is it possible to fill the matrix from top to bottom not from left to right?