How to open file array with fopen?

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Jacky
Jacky el 1 de Jul. de 2013
Hi, I have a list of files that look like this:
J={'File1', 'File2', 'File3'}
It is not possible to open the file using fopen this way:
for i=1:length(J)
fid=fopen('J(1)', 'r')
%Some algorithms here...
fclose(fid)
end
Is there any possible way to use fopen by using looping? It seems like it only accepts the actual file name. Please help. Thanks!

Respuesta aceptada

Jonathan Sullivan
Jonathan Sullivan el 1 de Jul. de 2013
You just need to index into J properly. J looks to be a cell array so you need to use curly brackets.
Try replacing your fopen line with this
fid = fopen(J{i},'r');
  1 comentario
Jacky
Jacky el 1 de Jul. de 2013
It works. I thought I did that and it it didn't work. It must be something that I missed earlier on. Thank you so much for pointing that out for me.

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Walter Roberson
Walter Roberson el 1 de Jul. de 2013

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