finding location of numbers in matrix

I have a matrix of A= 65 x 500. I want to find the position (location) of data in 'A' which are above 300. It really giving me trobles can somebody help me with this?

I tried this but with no avail. Btw. the number of datapoints which are above 300 varies among rows.

for jj= 1:size(A,1)
[ i j]= find(A>300);
end

And this gives only the total number of data points. Not row wise. Any help

Answer 1

[Andrei Bobrov]

A=[2 3 4; 3 2 2 ;5 6 7]
[ii,jj]=find(A'>2)
out = accumarray(jj,ii,[],@(x){x'})

[Ede gerlderlands]

Thank you. It works

Answer 2

[the cyclist]

Just this one line gives all the (i,j) coordinates, for all rows.

[i j]= find(A>300);

So, if you are interested in row 7 (for example), then find where i=7, and look at the corresponding values of j.

If you absolutely must do it separately for each row (for reasons you do not explain here), then you could do

for ii= 1:size(A,1)
  j{ii} = find(A(ii,:)>300);
end

The ii th element of the cell array will have the indices for row ii.

[Ede gerlderlands]

To put it simpler . If I have A=[2 3 4; 3 2 2 ;5 6 7] and If I want the location of points for A>2 for each row. What I expect is for each row is something like this

   2 3

   1 

   1 2 3

[Ede gerlderlands]

Thank you I have got it...

Answer 3

[Azzi Abdelmalek]

 [ii,jj]=find(A>300)

[Ede gerlderlands]

Thank you .This gives the position of total number of data points which are greater than 300. Not the position within each row.

[Azzi Abdelmalek]

for k=1:size(A,1)
    idx{k}=find(A(k,:)>300)
end

Answer 4

[Azzi Abdelmalek]

id=arrayfun(@(x) find(A(x,:)>300),(1:size(A,1))','un',0)