Need half of my contour plot

Hello I have a contour of the pressures over a surface. Basically, I had vectors x and y which were locations on the surface and on each location, I had a value for pressure. I have a rectangular plot. I was wondering if there is a way to split my plot from the diagonal and show just the results for either upper or lower triangles?

Answer 1

[Kye Taylor]

Check out the tril and triu functions. For example if you have data similar to

[x,y]= meshgrid(-1:.05:1);
z = x.^2+y.^2;
contour(x,y,z)

Try something like

zLowerTri = tril(z);
contour(x,y,zLowerTri)

Since contour plots with the origin at lower left instead of upper right, you may prefer either

zLowerTri = tril(z);
contour(x,y,zLowerTri)
axis ij

or

contour(x,y,fliplr(tril(fliplr(z))))

[Maryam]

Thank you very much for your response. Actually, it cuts the contour from another diagonal. Is there any way to do it for the other diagonal? Also, is there any way to show the deleted part in white?

[Maryam]

I used "contour(x,y,fliplr(tril(fliplr(z))))" and I got what I wanted. Thank you very much. I now need to Also, to show the deleted parts in white? Is there any way to do that? In the deleted area, my contour is all red which corresponds to the value=0 in my color map.

[Pourya Alinezhad]

use "nan" as i mentioned below to make that part invisible... functions you use {ex:tril(z)} replace the data values with zero,which itself could be a data!!!

[Maryam]

Thank you very much. I now have what I wanted.

Answer 2

[Pourya Alinezhad]

hello maryam, run following lines of code.

x=0:0.1:10;
  y=x;
  j=1;
  z=meshgrid(x,y);
  h=ones(length(x),length(x))*nan;
  for i=1:length(x)
      for j=1:length(y)
      if i>j
          h(i,j)=z(i,j);
      end
      end 
  end
  surf(sin(h)./sqrt(h))
  figure
  contourf(sin(h)./sqrt(h))