Sort fields of struct by length and alphabetically

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Michel C
Michel C el 20 de Mayo de 2021
Comentada: KAE el 20 de Ag. de 2021
I've been trying to sort the fields of a struct by combination of length and name. Length should take precedence, but if the length of two or more fields is equal (for example if they are scalar), those should be sorted alphabetically (within that group), where names starting with capital letter should take precedence. I'm coming up with nothing that works. Anybody?
Best regards MC

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Stephen23
Stephen23 el 20 de Mayo de 2021
Editada: Stephen23 el 20 de Mayo de 2021
S.aa = rand(3,1);
S.bb = 1;
S.cc = rand(8,2);
S.dd = 1;
S.Ee = 1;
S.Ff = rand(3,1)
S = struct with fields:
aa: [3×1 double] bb: 1 cc: [8×2 double] dd: 1 Ee: 1 Ff: [3×1 double]
Method one: sort and indexing:
N = structfun(@numel,S);
F = fieldnames(S);
[~,X] = sort(F);
[~,Y] = sort(N(X),'descend');
Z = orderfields(S,F(X(Y)))
Z = struct with fields:
cc: [8×2 double] Ff: [3×1 double] aa: [3×1 double] Ee: 1 bb: 1 dd: 1
Method two: table and sortrows:
[~,X] = sortrows(table(N,F),[-1,2]);
Z = orderfields(S,F(X))
Z = struct with fields:
cc: [8×2 double] Ff: [3×1 double] aa: [3×1 double] Ee: 1 bb: 1 dd: 1

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